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GaryK [48]
1 year ago
9

If we apply a potential difference of 4. 50 v between the ends of a wire that is 2. 50 m in length and 0. 654 mm in radius, the

resulting current through the wire is 17. 6. What is the resistivity of the wire material?.
Physics
1 answer:
tatyana61 [14]1 year ago
8 0

According to the resistance, the resistivity of wire material is 1.37 x 10¯⁷ Ωm.

We need to know about the resistance of conductive material to solve this problem. Resistance can be defined as the ratio of the voltage applied to current flow It can be written as

R = V / I

where R is resistance, V is voltage and I is current.

The resistance of the material depends on its resistivity and follows this equation

R = ρ . L / A

where ρ is resistivity, L is the length of the material and A is the surface.

From the question above, we know that

V = 4.5 V

L = 2.5 m

r = 0.654 mm = 6.54 x 10¯⁴ m

I = 17.6 A

Find the surface area

A = π . r²

A = π . ( 6.54 x 10¯⁴ )²

A = 1.34 x 10¯⁶ m²

Find the resistivity of the wire

R = V / I

ρ . 2.5 / (1.34 x 10¯⁶)= 4.5 / 17.6

ρ = 1.37 x 10¯⁷ Ωm

Find more on resistance at: brainly.com/question/17563681

#SPJ4

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Helpp pls
Kipish [7]

Answer:

The intensity of the electric field is

|E|=10654.37 \:N/C

Explanation:

The electric field equation is given by:

|E|=k\frac{q}{d^{2}}

Where:

  • k is the Coulomb constant
  • q is the charge at 0.4100 m from the balloon
  • d is the distance from the charge to the balloon

As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.

Then, let's use the equation written above.

|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}

|E|=10654.37 \:N/C

I hope it helps you!

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