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madreJ [45]
3 years ago
8

How much does the Earth weigh? Why does the moon appear in the daytime?

Physics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

moon disappear because of the rotation

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A wave has a wavelength of 10mm and a frequency of 5 hz what is the speed?
geniusboy [140]
V=fλ
v=5*0.01
Therefore v=0.05
3 0
3 years ago
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Which conclusion, based on measurements of the ball in the lab in this lesson, is correct? a. The density of the ball was 1.48 g
ser-zykov [4K]

Answer:

u dummy

Explanation:

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3 years ago
HELP ME PLEASE! MOTION CONCEPT MAP!
Zinaida [17]

a. speed b. direction c. Magnitude d. Direction

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A block of mass 0.510 kg is pushed against a horizontal spring of negligible mass until the spring is compressed a distance x. T
maria [59]

Answer:

x=0.46m, speed=7.9m/s

Explanation:

Using the concept of conservation of energy:

1. kinetic energy of mass m and velocity v: E_k=\frac{1}{2}mv^2

2. gravitational potential energy of mass m, grav. acc. g and height h: E_g=mgh

3. potential energy in a spring with spring constant k and displacement from equilibrium x: E_s=\frac{1}{2}kx^2

Calculating x:

\frac{1}{2}mv_a^2=\frac{1}{2}kx^2

x=\sqrt{\frac{m}{k}}v_a

Calculating the speed:

\frac{1}{2}mv_a^2 +mgh_a=\frac{1}{2}mv_b^2+mgh_b + W_{friction}

h_a=0, h_b=2R,W_{friction}=F_{friction}\times distance=7\pi R

\frac{1}{2}mv_a^2=\frac{1}{2}mv_b^2+2mgR+7\pi R

Solving for v_b:

v_b=\sqrt{v_a^2-4gR-14\pi\frac{R}{m}}

7 0
3 years ago
The electric field between the plates of the cathode ray tube of an older television set can be as high as 2.5x104 N/C. Determin
pentagon [3]

Answer:

(a) F = -4.01 * 10^{-15} N

(b) a = 4.40 * 10^{15} m/s^2

Explanation:

Parameter given:

Electric field, E = 2.5 * 10^4 N/C

(a) Electric force is given (in terms of electric field) as a product of electric charge and electric field.

Mathematically:

F = qE

Electric charge, q, of an electron = - 1.602 * 10^{-19} C

F = -1.602 * 10^{-19} * 2.5 * 10^4\\\\\\F = -4.01 * 10^{-15} N

(b) This electrostatic force causes the electron to accelerate with an equivalent force:

F = -ma

where m = mass of an electron

a = acceleration of electron

(Note: the force is negative cos the direction of the force is opposite the direction of the electron)

Therefore:

-ma =  -4.01 * 10^{-15} N\\\\\\a = \frac{-4.01 * 10^{-15}}{-m}

Mass, m, of an electron = 9.11 * 10^{-31} kg

=> a = \frac{-4.01 * 10^{-15}}{-9.11 * 10^{-31}}\\\\\\a = 4.40 * 10^{15} m/s^2

The acceleration of the electron is 4.40 * 10^{15} m/s^2

5 0
3 years ago
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