What is most often given a value of zero to describe an object position on a srtaight line

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 o

shepuryov [24]

Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

From the question we are told that

The random sample is $n = 15$

The mean weight is $\= x = 3.8\ ounce$

The standard deviation is $\sigma = 0.5 \ ounce$

The level of significance is $\alpha = 0.05$

So

The null hypothesis is $H_o : \mu \ge 4$

The alternative hypothesis is $H_a : \mu < 4$

Generally the critical value which a bench mark to ascertain whether the null hypothesis is true or false is mathematically represented as

$t_{0.05} = 1.79$

This value is obtained from the critical value table

Generally the test statistics is mathematically represented as

$Test \ Statistics (ST) = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} } }$

=> $ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }$

$ST = - 1.79$

So since ST is less than $t_{0.05}$ then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

Thus the true mean weight is less than 4

4 0

3 years ago

A capacitance C and an inductance L are operated at the same angular frequency.

PIT_PIT [208]

Answer:

(B) 7279.70 rad/sec (C) $X_L=37.1265\ ohm\ and \ X_C=37.1265\ ohm$

Explanation:

We have given $L=5.10mH$ and $C=3.70\mu F$

(B) The angular frequency is denoted as $\omega$ whose value is given by $\omega =\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{5.10\times 10^{-3}\times 3.70\times 10^{-6}}}=7279.70\ rad/sec$