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klasskru [66]
3 years ago
9

What is most often given a value of zero to describe an object position on a srtaight line

Physics
1 answer:
Vsevolod [243]3 years ago
6 0
Reference point is most often given a value of zero to describe an object's position on a straight line
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You are given two positively charged particles, of equal magnitude, separated by a distance, "d". What will happen to the force
gizmo_the_mogwai [7]

force goes as 1/d^2 ... (2d)^2 => 4d^2 ...

C) decrease by a factor of four

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3 years ago
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Two gliders on an air track collide in a perfectly elastic collision. Glider A has a mass of 1.1 kg and is initially travelling
Eva8 [605]

m1= mass 1 = 1.1 kg

Vi1 = initial velocity 1 = 2.7 m/s

m2= 2.4 kg

V2i = -1.9 m/s

We assume east as positive and west as negative.

Apply the formulas:

Vf1 = ?

vf1=(\frac{m1-m2}{m1+m2})Vi1+(\frac{2m2}{m1+m2})Vi2

Replacing:

Vf1=\frac{(1.1-2.4)}{(1.1+2.4)}2.7+\frac{(2\times2.4)}{(1.1+2.4)}-1.9Vf1=(\frac{-1.3}{3.5})2.7+(\frac{4.8}{3.5})-1.9Vf1=-1-2.6=-3.6\text{ m/s}

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1 year ago
When sand absorbs the electromagnetic waves of the sun it becomes warm through the process of
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I believe the answer is radiation
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3 years ago
Calculate the kinetic energy of Earth due to its spinning about its axis. Krot = J Compare your answer with the kinetic energy o
Studentka2010 [4]

Answer:

Explanation:

Answer: Let ke = 1/2 IW^2 = 1/2 kMr^2 W^2 be Earth's rotational KE. W = 2pi/24 radians per hour rotation speed and k = 2/5 for a solid sphere M is Earth mass, r = 6.4E6 m.

Then ke = 1/2 2/5 6E24 (6.4E6)^2 (2pi/(24*3600))^2 = ? Joules. You can do the math, note W is converted to radians per second for unit consistency.

Let KE = 1/2 KMR^2 w^2 be Earth's orbital KE. w = 2pi/(365*24) radians per hour K = 1 for a point mass. Note I used 365 days, a more precise number is 365.25 days per year, which is why we have Leap Years.

Find KE/ke = 1/2 KMR^2 w^2//1/2 kMr^2 W^2 = (K/k)(w/W)^2 (R/r)^2 = (5/2) (365)^2 (1.5E11/6.4E6)^2 = 7.81E9 ANS

8 0
4 years ago
How many meters are in 6 kilometers?
lukranit [14]

Answer:

6000 kilometers

Explanation:

multiply the length value by 1000

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