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3 years ago

What is most often given a value of zero to describe an object position on a srtaight line

Physics

1 answer:

Vsevolod [243]3 years ago

6 0

Reference point is most often given a value of zero to describe an object's position on a straight line

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This chart shows characteristics of three different types of waves.

prohojiy [21]

Answer:

1. Primary or P waves are push and pull waves

2. Secondary, S or Shear Waves are also called transverse wave

3. L or surface waves reach the earth's surface after P and S waves

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3 years ago

The three different states of matter are liquid, solid, and gas. A solid is something you can hold in your fingers, while a liqu

nika2105 [10]

The answer is C. that liquids and gases both take the shape of their container.

Think of it this way, if you take an ice cube and put it in your glass, it will stay in its shape and stay that way until it melts. But if you put liquid or a gas into a glass, it will take the shape of the glass that it is put into.

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4 years ago

Read 2 more answers

An 85,000 kg stunt plane performs a loop-the-loop, flying in a 260-m-diameter vertical circle. at the point where the plane is f

konstantin123 [22]

A) When the plane is flying straight down, there are three forces acting on it:
- the centripetal force $F=m \frac{v^2}{r}$ , directed toward the center of the circle (so, horizontally)
- the weight of the plane: $W=mg$ , downward, so vertically
- a third force, given by the propulsion of the plane, which is accelerating it towards the ground (because the problem says that the plane has an acceleration of a=12 m/s^2 towards the ground)

The radius of the circle is $r= \frac{260 m}{2} = 130 m$ , so the centripetal force acting on the plane is
$F_c=m \frac{v^2}{r} = \frac{(85000 kg)(55 m/s)^2}{130 m}=1.98 \cdot 10^6 N$
On the vertical axis, we have two forces: the weight
$W=mg=(85000 kg)(9.81 m/s^2)=8.34 \cdot 10^5 N$
and the other force F given by the propulsion. Since we know that their sum should generate an acceleration equal to $a=12 m/s^2$ , we can find the magnitude of this other force F by using Newton's second law:
$F+mg=ma$
$F=m(a-g)=(85000kg)(12 m/s^2-9.81 m/s^2)=1.86 \cdot 10^5 N$

So, the net force acting on the plane will be the resultant of the centripetal force (acting in the horizontal direction) and the two forces W and F (acting in the vertical direction):
$R= \sqrt{(F_c^2+(W+F)^2}=$
$= \sqrt{(1.98\cdot 10^6N)^2+(8.34 \cdot 10^5N+1.86 \cdot 10^5 N)^2} =2.23 \cdot 10^6 N$

(b) The tangent of the angle with respect to the horizontal is the ratio between the sum of the forces in the vertical direction (taken with negative sign, since they are directed downward) and the forces acting in the horizontal direction, so:
$\tan \theta = \frac{-(W+F)}{F_c}= -0.5$
And so, the angle is
$\theta = \arctan (-0.5)=-26.8 ^{\circ}$

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3 years ago

The swim bladder of a fish helps keep the fish from sinking by_______.

Slav-nsk [51]

Answer:

C. Increasing its buoyancy

6 0

3 years ago

Read 2 more answers

A bird flies due north with a speed of 15 m/s relative to the air. The air moves due west with a speed of 11 m/s relative to the

Aleksandr [31]

Answer:

I'm not sure if the directions affect the speed tho

but I think it's 4? cause it's the speed relative to the ground

hope this helps:))

4 0

3 years ago