Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
Answer:
1/2.
Step-by-step explanation:
There seem to be a couple prominent points on the line. We can use two of them to find the slope.
(0, 75)
(30, 90)
(90 - 75) / (30 - 0) = 15 / 30 = 3 / 6 = 1/2.
Hope this helps!
Answer:
The surface area of the figure is 352 cm².
Step-by-step explanation:
Given:
Length(l) = 12 cm.
Width(w) = 4 cm.
Height(h) = 8 cm.
Now, to find the surface area.
By putting the formula to get the surface area:
Surface area = 2(l×w+w×h+h×l)
Therefore, the surface area of the figure is 352 cm².
Answer:
it is - 72 are 0
Step-by-step explanation:
Answer:
Solution: 
,
Step-by-step explanation:
Given:
The rational equation to solve is given as:
Doing cross product, we get:
Now, for , the rational equation is equal to 0. So, is a solution.
Also, is also a solution.
So, no extraneous solution.
