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RUDIKE [14]
1 year ago
11

light of wavelength 3.0 × 10−7 m shines on the metals lithium, iron, and mercury, which have work functions of 2.3 ev, 3.9 ev, a

nd 4.5 ev, respectively. which of these metals will exhibit the photoelectric effect? the speed of light is 3 × 108 m/s and planck’s constant is 6.63 × 10−34 j · s.
Physics
1 answer:
Greeley [361]1 year ago
8 0

None of these will show photoelectric effect as for photoelectric effect energy must be greater than work function.

a stream of particles whose energy follow the Planck formula for their frequencies. The photons and atoms collide when that beam strikes a metal. The photoelectric effect is created by a collision when a photon's frequency is high enough to remove an electron.

Here we have;

Light of wavelength = 3× 10∧-7

Speed of light= 3×10∧8

plank's constant= 6.63×10∧-34

Therefore, E=hc/lambda=6.63×10∧-19=6.63ev

as you can  see none of wave function is greater than energy so no one will show photoelectric effect. The frequency of the incident radiation and the surface material are the two elements controlling the maximum kinetic energy of photoelectrons.

Learn more about photoelectric effect here; brainly.com/question/9260704?

#SPJ4

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Density is a physical property that relates the mass of a substance to its volume. A. Calculate the density, in g/mL , of a liqu
Angelina_Jolie [31]

Answer:

A) 0.660 g/ml

B) 1.297 ml

C) 0.272 g

Explanation:

Every substance, body or material has mass and volume, however the mass of different substances occupy different volumes.  This is where density D appears as a  physical characteristic property of matter that establishes a relationship between the mass m of a body or substance and the volume V it occupies:

D=\frac{m}{V} (1)

Knowing this, let's begin with the answers:

<h2 /><h2>Answer A:</h2>

Here the mass is m=0.155g and th volume V=0.000235L=0.235mL

Solving (1) with these values:

D=\frac{0.155g}{0.235mL} (2)

D=0.660g/mL (3)

<h2>Answer B:</h2>

In this case the mass of a sample is m=4.71g and its density is D=3.63g/mL.

Isolating V from (1):

V=\frac{m}{D} (4)

V=\frac{4.71g}{3.63g/mL} (5)

V=1.297mL (5)

<h2>Answer C:</h2>

In this case the volume of a sample is V=0.293mL and its density is D=0.930g/mL.

Isolating m from (1):

m=D.V (6)

m=(0.930g/mL)(0.293mL) (7)

m=0.272g (8)

4 0
3 years ago
Read 2 more answers
If an engine does 660 J of work in 10 seconds, its average power is ...
givi [52]

Answer:

66w

Explanation:

p=w/t

p=660/10

p=66

prolly a bad explanation but hope it helps...

4 0
3 years ago
Which would BEST describes what occurs when a ball is thrown against a wall? A) The ball will not bounce off the wall. B) The ba
oee [108]

Answer:

D) The ball exerts a force on the wall and the wall exerts a force back.

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force on another object B, then object B exerts an equal and opposite force on object A"

In this problem, we can identify (for instance) object A with tha ball and object B with the wall. Therefore, if we apply Newton's third law, we get:

The ball (object A) exerts a force on the wall (object B), therefore the wall (object B) exerts an equal and opposite force on the ball (object A). So, option D is the correct one.

3 0
4 years ago
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Which of the following is correct in order of lowest to highest energy?
Serggg [28]
It is number 3. Because microwaves are the lowest of the sepectum then visible light the the highest of them all is Gamma Ray's. Hope this helps!!
3 0
3 years ago
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A pendulum consists of a large balanced mass hanging on the end of a long wire. At the point where a 28-kg pendulum has the grea
Ray Of Light [21]

Answer:

The length of the wire is approximately 67.1 m

Explanation:

The parameters of the pendulum are;

The mass of the pendulum, m = 28 kg

The angle between the pendulum weight and the wire, θ = 89°

The magnitude of the torque exerted by the pendulum's weight, τ = 1.84 × 10⁴ N·m

We have;

Torque, τ = F·L·sinθ = m·g·l·sinθ

Where;

F = The applies force = The weight of the pendulum = m·g

g = The acceleration due to gravity ≈ 9.8 m/s²

l = The length of the wire

Plugging in the values of the variables gives;

1.84 × 10⁴ N·m = 28 kg × 9.8 m/s² × l × sin(89°)

Therefore;

l = 1.84 × 10⁴ N·m/(28 kg × 9.8 m/s² ×  sin(89°)) = 67.0656080029 m ≈ 67.1 m

The length of the wire, l ≈ 67.1 m

6 0
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