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RUDIKE [14]
1 year ago
11

light of wavelength 3.0 × 10−7 m shines on the metals lithium, iron, and mercury, which have work functions of 2.3 ev, 3.9 ev, a

nd 4.5 ev, respectively. which of these metals will exhibit the photoelectric effect? the speed of light is 3 × 108 m/s and planck’s constant is 6.63 × 10−34 j · s.
Physics
1 answer:
Greeley [361]1 year ago
8 0

None of these will show photoelectric effect as for photoelectric effect energy must be greater than work function.

a stream of particles whose energy follow the Planck formula for their frequencies. The photons and atoms collide when that beam strikes a metal. The photoelectric effect is created by a collision when a photon's frequency is high enough to remove an electron.

Here we have;

Light of wavelength = 3× 10∧-7

Speed of light= 3×10∧8

plank's constant= 6.63×10∧-34

Therefore, E=hc/lambda=6.63×10∧-19=6.63ev

as you can  see none of wave function is greater than energy so no one will show photoelectric effect. The frequency of the incident radiation and the surface material are the two elements controlling the maximum kinetic energy of photoelectrons.

Learn more about photoelectric effect here; brainly.com/question/9260704?

#SPJ4

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What is the speed of an object that travels 60 metres in 4 seconds​
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Answer:

s =  \frac{d}{t}  =  \frac{60}{4}  \\  \boxed{speed = 15m. {sec}^{ - 1} }

4 0
2 years ago
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A 25-kg wagon has a momentum of 300kg m/s. What is it’s acceleration?
arsen [322]

The answer is 12 ....

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3 years ago
Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she
Alex777 [14]

Answer

200km {h}^{ - 2}

Explanation

Acceleration =  \frac{final \:  \:  \: velocity - initial \:  \: velocity }{time}  \\  =  \frac{(40 - 30)km {h}^{ - 1} }{0.05h}  \\  =  \frac{10}{0.05}  \\  = 200km {h}^{ - 2}

Hope this helps you.

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3 years ago
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You are a crane operator using a wrecking ball to demolish an old building. You can choose to use a 100-kg ball or a 150-kg ball
Elenna [48]

Answer:

The answer to the question is

The two balls, although of different masses, could be made to have the same demolishing force by setting the velocity of the 100 kg ball to 1.5 times the velocity of the 150 kg ball.

That is if V₁ is the velocity of the 150 kg ball and  V₂ is the velocity of the 100 kg ball then V₂  = 1.5×V₁ for the demolishing effect of the two balls to be equal.

Explanation:

To answer the we are required to explain the meaning of momentum and state its properties

Momentum is a physical property of an object in motion. It indicates the amount of motion inherent in the object.  An object in motion is said to have momentum

The types of momentum possessed by an object can be classified into either

1, Linear momentum or

2. Angular momentum

An object moving with a velocity, v has linear momentum while a spinning object has an angular momentum

The momentum is given by the formula

P = m × V

Where m = mass and

V = velocity

Newtons second law of motion states that, the force acting on an object is equivalent to the rate of change of momentum produced and acting in the direction of the force

Properties of momentum

From the above statements it means that the two balls can be made equivalent by having the appropriate amount of speed. That iis the two balls can have the same momentum thus for equal momentum effect, we have

150 kg × V₁ = 100 kg × V₂

or V₂ = 1.5×V₁

3 0
3 years ago
The temperature and time t given in hours from 0 to 24 after midnight in downtown mathville is given by t=10-5 sin(pi/12 t) degr
Dvinal [7]

Answer:

T_A_v_g=9.918192559$^{\circ}C

Explanation:

The problem tell us that the temperature as function of time in downtown mathville is given by:

T(t)=10-5*sin(\frac{\pi}{12t})

The average temperature over a given interval can be calculated as:

T_a_v_g=\frac{T_o+T_f}{2}

Where:

T_o=Initial\hspace{3}temperature\\T_f=Final\hspace{3}temperature

So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:

Therefore:

T_o=T(12)=10-5*sin(\frac{\pi}{12*12}) =9.890925575$^{\circ}C

T_f=T(24)=10-5*sin(\frac{\pi}{12*24}) =9.945459543$^{\circ}C

Hence, the average temperature between noon and midnight is:

T_A_v_g=\frac{9.890925575+9.945459543}{2}=9.918192559$^{\circ}C

3 0
3 years ago
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