Identify which best describes the energy used to pluck guitar strings to make sound.

2 answers:

8 0

<span>The correct answer is: Mechanical Energy

Explanation:
As the guitar strings are plunked, the potential energy stored in the strings has an ability to make them vibrate. When the strings are vibrating, that potential energy is actually converted to the kinetic energy. Hence, the whole phenomena contains both the kinetic energy and the potential energy. The sum of kinetic energy and the potential energy is called Mechanical energy. Therefore, the correct answer is Mechanical Energy.</span>

kotykmax [81]3 years ago

6 0

The answer is mechanical energy

You might be interested in

Release an electron initially at rest in the presence of an electric field. The electron tends to go to the region of 1. same el

olga nikolaevna [1]

Answer:

The electron tends to go to the region of 4. higher electric potential.

Explanation:

When a charged particle is immersed in an electric field, it experiences a force given by

$F=qE$

where

q is the charge of the particle

E is the electric field

The direction of the force depends on the sign of the charge. In particular:

- The force and the electric field have the same direction if the charge is positive

- The force and the electric field have opposite directions if the charge is negative

Therefore, an electron (negative charge) moves in the direction opposite to the electric field lines.

However, electric field lines go from points at higher potential to points at lower potential: so, electrons move from regions at lower potential to regions of higher potential.

Therefore, the correct answer is

The electron tends to go to the region of 4. higher electric potential.

4 0

4 years ago

Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open,

Sphinxa [80]

The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm

7 0

3 years ago

(a) Calculate the linear acceleration of a car, the 0.220-m radius tires of which have an angular acceleration of 11.0 rad/s2. A

Alisiya [41]

Answer:

The value is $a_t = 2.42 \ m/s^2$