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GenaCL600 [577]
2 years ago
10

PLSS HELP ASAP

Physics
2 answers:
Feliz [49]2 years ago
6 0
40 seconds I’m pretty sure sorry if I’m wrong
LenaWriter [7]2 years ago
5 0

Answer:d) 30 sec

Explanation:

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Young's interference experiment demonstrated the particle nature of light T/F?
MAVERICK [17]
I think the answer is false

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3 years ago
The diagram below shows a wave with its wavelength indicated in red.
lisabon 2012 [21]

C. It will decrease


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4 years ago
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For this problem, we assume that we are on planet-i. the radius of this planet is r =4200 km, the gravitational acceleration at
Minchanka [31]
The expression commonly used for potential gravitational energy is just simplification. It is actually just the first term in Taylor expansion of the real expression. 
In general, the potential energy of gravitational field is defined as:
U=-G \frac{mM}{r}
Where G is universal gravitational constant, and r is the distance between the objects centers of mass. Negative sign represents the bound state.
Since we are not given the mass of the planet we have to calculate it.
F_g=G\frac{mM}{r_p^2}\\ mg=G\frac{mM}{r_p^2}\\ g=G\frac{M}{r_p^2}
This formula can be used for any planet. It gives you the gravitational acceleration on the planet's surface. We can use it to calculate the planet's mass:
g=G\frac{M}{r_p^2}\\ M=\frac{gr_p^2}{G}=2.41\cdot 10^{24}kg
Now we can calculate the potential energy of that cannonball when it reaches its maximum height.
U=-G \frac{mM}{r}\\ U=-G \frac{mM}{r_p+h}
When we plug in the numbers we get:
U=-4.99\cdot 10^{10} J
The potential energy has to be equal to the kinetic energy.
E_k=4.99\cdot 10^{10} J

3 0
3 years ago
For how long should a force of 50,0 N be applied to change the momentum of an object
patriot [66]

Answer:

2,4 second

Explanation:

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12 = 50 .t

12/50 = t

2,4

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nasty-shy [4]
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3 years ago
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