Answer:
7.5 g
Explanation:
There is some info missing. I think this is the original question.
<em>Ammonium phosphate ((NH₄)₃PO₄) is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid (H₃PO₄) with ammonia (NH₃). What mass of ammonium phosphate is produced by the reaction of 4.9 g of phosphoric acid? Be sure your answer has the correct number of significant digits.</em>
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Step 1: Write the balanced equation
H₃PO₄ + 3 NH₃ ⇒ (NH₄)₃PO₄
Step 2: Calculate the moles corresponding to 4.9 g of phosphoric acid
The molar mass of phosphoric acid is 98.00 g/mol.

Step 3: Calculate the moles of ammonium phosphate produced from 0.050 moles of phosphoric acid
The molar ratio of H₃PO₄ to (NH₄)₃PO₄ is 1:1. The moles of (NH₄)₃PO₄ produced are 1/1 × 0.050 mol = 0.050 mol.
Step 4: Calculate the mass corresponding to 0.050 moles of ammonium phosphate
The molar mass of ammonium phosphate is 149.09 g/mol.

Explanation:
been defined in such a way. It is defined as the numbers of particles in 12 g of 12C. If it were 24 g instead of 12 g, then the weight of 1 mole of substance would equal 2 times the atomic/molecular mass in grams.
To solve the equation for Mass, rearrange the equation by multiplying both sides timesVolume in order to isolate Mass, then plug in your known values (Density and Volume). Then solve for Mass.
D is the answer its Atoms are mostly empty space with small, dense, positively charged centers.
The production of
is
. Converting mass into kg,
1 ton=907.185 kg, thus,

Thus, production of
will be
.
The specific volume of
is
.
Volume of
produced per day can be calculated as:

Putting the values,

Thus, volume of
produced per year will be:

Thus, in 4 year volume of
produced will be:
