Question

The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric).a proposal has been made to capture and sequester the co2 at approximately 300 k and 140 atm. at these conditions, the specific volume of co2 is estimated to be 0.0120 m3/kg.what volume of co2 would be collected in a 4.00 year period?

Answer 1

The production of $CO_{2}$ is $3.3480\times 10^{4} tons/day$. Converting mass into kg,

1 ton=907.185 kg, thus,

$3.3480\times 10^{4} tons=3.037\times 10^{7} kg$

Thus, production of $CO_{2}$ will be $3.037\times 10^{7} kg/ day$.

The specific volume of $CO_{2}$ is $0.0120 m^{3}/kg$.

Volume of $CO_{2}$ produced per day can be calculated as:

$V=Specific volume\times mass$

Putting the values,

$V=0.0120 m^{3}/kg\times 3.037\times 10^{7} kg=364440 m^{3}/day$

Thus, volume of $CO_{2}$ produced per year will be:

$V=\frac{365 days}{1 year}(364440 m^{3}/day)=1.33\times 10^{8}m^{3}/year$

Thus, in 4 year volume of $CO_{2}$ produced will be:

$V=1.33\times 10^{8}m^{3}/year\times 4 years=5.32\times 10^{8}m^{3}$