Answer:
4.16
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:
pH=pKa+log[base]/[acid]
Where Ka is the dissociation constant of the acid.
Given that:
pKa = 3.86
Given, concentration of acid = [acid] = 0.4 M
concentration of base = [base] = 0.8 M
So,
pH=3.86+log(0.8/0.4) = 4.16
Answer:
S. aureus strain is less infectious, but its alpha-toxin is highly-toxic.
Explanation:
Given data:
LD50 for S. aureus alpha toxin 0.45 \mu g/kg
ID50 for same mouse density found to be 200,000
From the data information given above Staphylococcus aureus was done on mice. The result show that LD50 is found to be 0.45\mu g/kg and ID50 found to be 200,000 on same mouse population
the result taken together mean that S. aureus strain is less infectious, but its alpha-toxin is highly-toxic.
In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N.
N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 = +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is = -3
From moles to grams C4H10 weighs 174.3666grams
Answer:
During the prophase of mitosis, the chromatin in a cell compacts to form condensed chromosomes; this condensation is required in order for the cell to divide properly. While mitotic cells have condensed chromosomes, interphase cells do not.
Explanation:
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