laboratory stock solution is 1.50 M NaOH. Calcul. Show transcribed image text A laboratory stock solution is 1.50 M NaOH. Calculate the volume of this stock solution that would be needed to prepare 300. ml
Answer:
a common industrial use for a mineral is:
Explanation:
Typical examples of industrial rocks and minerals are limestone, clays, sand, gravel, diatomite, kaolin, bentonite, silica, barite, gypsum, and talc.
Answer:
0.027g
Explanation:
From Avogadro's hypothesis, 1mole of any substance contains 6.02x10^23 molecules.
From the above, it means that 1mole of SO3 also contains 6.02x10^23 molecules.
1mole of SO3 = 32 + (16x3) = 32 + 48 = 80g
If 1 mole (80g) of SO3 contains 6.02x10^23 molecules,
Then Xg of SO3 will contain 2x10^20 molecules i.e
Xg of SO3 = (80x2x10^20)/6.02x10^23 = 0.027g
Answer: 36 mol H2O (l)
Explanation:
Let's use stoichiometry to solve this problem.
12 mol C2H6 * (6 mol H2O / 2 mol C2H6) = 36 mol H2O
Hope this helps!
<span>Dry cell battery
When an automotive battery is fully charged, the sulfuric acid and water mixture will have a specific gravity of about 1.3. Specific gravity is actually the difference in the weight of water in comparison to a specific fluid. It is measured by a hydrometer. The amount of charge in the battery is normally measured by the specific gravity of the battery. The specific gravity of water is 1 and anything less than one is considered less dense while anything that has a specific gravity of more than 1 is considered more dense than water. </span>
