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sineoko [7]
2 years ago
14

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2

2.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?
Chemistry
1 answer:
Assoli18 [71]2 years ago
8 0

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

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This question is incomplete.

Explanation:

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If 316 mL nitrogen is combined with 178 mL oxygen, what volume of N2O is produced at constant temperature and pressure if the re
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Answer;

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7 0
3 years ago
Read 2 more answers
Question 6 (3 points)
olga55 [171]

Answer:

Explanation:

Given parameters:

Molarity of KOH = 0.26M

Volume of H₂SO₄ = 19.76mL

Molarity of H₂SO₄ = 0.20M

Unknown:

Volume of KOH = ?

Solution:

This is a neutralization reaction in which an acid reacts with a base to produce salt and water:

         H₂SO₄     +     2KOH      →    K₂SO₄    +     2H₂O

 We solve from the known to the unknown in the reaction.

The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:

       Number of moles of acid = molarity x volume

       Number of moles of acid = 19.76 x 0.20 = 3.95mol

From the balanced reaction equation:

      1 mole of acid reacts with 2 moles of the bases KOH

     3.95mole of acid would react with 3.95moles x 2 of the base

  Number of moles of reacting base = 7.90moles

To find the volume of base;

  Volume of base = \frac{number of moles of base}{molarity}

   Volume = \frac{7.90}{0.26} = 30.40mL

Learn more:

Neutralization brainly.com/question/6447527

#learnwithBrainly

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