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lora16 [44]
4 years ago
14

Write balanced complete ionic equation for hcl(aq)+lioh(aq)→h2o(l)+licl(aq)

Chemistry
2 answers:
DedPeter [7]4 years ago
8 0

The balanced complete ionic equation is \boxed{{{\text{H}}^ + }\left( {aq} \right) + {\text{C}}{{\text{l}}^ - }\left( {aq} \right) + {\text{L}}{{\text{i}}^ + }\left( {aq} \right) + {\text{O}}{{\text{H}}^ - }\left( {aq} \right) \to {{\text{H}}_2}{\text{O}}\left( l \right) + {\text{L}}{{\text{i}}^ + }\left( {aq} \right) + {\text{C}}{{\text{l}}^ - }\left( {aq} \right)}.

Further Explanation:

The three types of equations that are used to represent the chemical reaction are as follows:

1. Molecular equation

2. Total ionic equation

3. Net ionic equation

The reactants and products remain in <em>undissociated</em> form in the <em>molecular equation</em>. In the case of <em>total ionic equation</em>, all the ions that are <em>dissociated</em> and present in the reaction mixture are represented while in the case of net or overall ionic equation only the useful ions that participate in the reaction are represented.

The steps to write the net ionic reaction are as follows:

Step 1: Write the molecular equation for the reaction with the phases in the bracket.

In the reaction, HCl reacts with LiOH to form LiCl and {{\text{H}}_{\text{2}}}{\text{O}}. The balanced molecular equation of the reaction is as follows:

{\text{HCl}}\left({aq}\right)+{\text{LiOH}}\left({aq}\right)\to{{\text{H}}_{\text{2}}}{\text{O}}\left(l\right)+{\text{LiCl}}\left({aq}\right)

Step 2: Dissociate all the compounds with the aqueous phase to write the total ionic equation. The compounds with solid and liquid phases remain same. The total ionic equation is as follows:

{{\text{H}}^+}\left({aq}\right)+{\text{C}}{{\text{l}}^-}\left({aq}\right)+{\text{L}}{{\text{i}}^+}\left({aq}\right)+{\text{O}}{{\text{H}}^-}\left({aq}\right)\to{{\text{H}}_2}{\text{O}}\left(l\right)+{\text{L}}{{\text{i}}^+}\left({aq}\right)+{\text{C}}{{\text{l}}^-}\left({aq}\right)

Therefore, the complete ionic equation obtained is as follows:

{{\text{H}}^+}\left({aq}\right)+{\text{C}}{{\text{l}}^-}\left({aq}\right)+{\text{L}}{{\text{i}}^+}\left({aq}\right)+{\text{O}}{{\text{H}}^-}\left({aq}\right)\to{{\text{H}}_2}{\text{O}}\left(l\right)+{\text{L}}{{\text{i}}^+}\left({aq}\right)+{\text{C}}{{\text{l}}^-}\left({aq}\right)

Learn more:

1. Balanced chemical equation: brainly.com/question/1405182

2. Oxidation and reduction reaction: brainly.com/question/2973661

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: net ionic equation, complete ionic equation, Li+, OH-, Cl-, LiCl, HCl, H2O, LiOH, solid phase, liquid phase, aqueous phase.

olga2289 [7]4 years ago
4 0
<span>H and Li have a +1 charge. Cl and OH have a -1 charge. When written out it should look like this: H(+1) + Cl(-1) + Li(+1) + OH(-1) --> H2O + Li(+1) + Cl(-1) if you wanted the net ionic equation it would be: H(+1) + OH(-1) --> H2O</span>
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Answer:

42.8

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ve / vh = √( (2qV / me) ÷(2qV / mh) = √ ( mh / me ) where mh = mass of hydrogen ion and me is mass of electron, V voltage is the same, ve is speed of electron and vh is the speed of hydrogen ion

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8 0
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1 mole of hcl(g) has a greater entropy than 1 mole of hbr(g). true or false
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Reactivity and flammability are are examples of properties.​
nika2105 [10]

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How many grams of glycerine, C3H8O3, are needed to make 100. mL of 2.60 M solution?
Masteriza [31]

Answer:

the mass of the glycerine needed in the given solution is  23.92 g

Explanation:

Given;

molarity of the solution (C₃H₈O₃), C = 2.60 M

Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M

The molarity of a solution is given as follows;

Molarity = \frac{amount \ of \ solute \ (moles)}{volume \ of \ solution \ (L)} \\\\amount \ of \ solute \ (moles) = Molarity  \ \times volume \ of \ solution \ (L)\\\\amount \ of \ solute \ (moles) = 2.6 \times 0.1 \\\\amount \ of \ solute \ (moles) = 0.26 \ mole

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The mass of the glycerine needed in the given solution is calculated as follows;

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Therefore, the mass of the glycerine needed in the given solution is  23.92 g

7 0
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