Question

MARKING BRAINLIEST! please help asap, i need a and b, thank you

Answer 1

The time required to reduce the concentration from 0.00757 M to 0.00180 M is equal to 1.52 × 10⁻⁴ s. The half-life period of the reaction is 9.98× 10⁻⁵s.

What is the rate of reaction?

The rate of reaction is described as the speed at which reactants are converted into products. A catalyst increases the rate of the reaction without going under any change in the chemical reaction.

Given the initial concentration of the reactant, C₀= 0.00757 M

The concentration of reactant after time t is C₁= 0.00180 M

The rate constant of the reaction, k = 37.9 M⁻¹s⁻¹

For the first-order reaction: $C_t =C_0-kt$

0.00180 = 0.00757 - (37.9) t

t =  1.52 × 10⁻⁴ s

The half-life period of the reaction: $t_{\frac{1}{2} } =\frac{C_0}{2k}$

$t_{\frac{1}{2} } =\frac{0.00757}{2\times 37.9}$

Half-life of the reaction = 9.98 × 10⁻⁵s

Learn more about the rate of reaction, here:

brainly.com/question/13571877

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