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ruslelena [56]
3 years ago
12

which of the following cannot be considered a single phase? a) a pure solid b) a pure liquid c) a homogeneous mixture d) a heter

ogeneous mixture
Chemistry
1 answer:
Trava [24]3 years ago
8 0
The question is asking to choose among the following choices is cannot be considered as a single phase and base on my further research and understanding about the sad topic, I would say that the answer would be <span>d) a heterogeneous mixture. I hope you are satisfied with my answer </span>
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four students measured the mass of a piece of metal whose accurate mass is 34.75g. their result are 34.2g,33.75g,35.0g and 34.69
dedylja [7]

Answer:

the best estimate is 34.69 g

Explanation:

the best estimate is 34.69 gm because when it is rounded it becomes 34.70 gm which is near to actual weight 34.75 gms

4 0
3 years ago
Read 2 more answers
In sediments and waterlogged soil, dissolved O2 concentrations are so low that the microorganisms living there must rely on othe
kakasveta [241]

Answer:

1) SO₄ ²⁻ : (+6)

  H₂S : (-2)

Explanation:

a) <u>Sulfate reducers</u> are widespread in muds and other sediments, water-logged soils, etc., environments that contain SO₄ ²⁻ and become anoxic as a result of microbial decomposition.

Sulfate (SO₄ ²⁻), the most oxidized form of sulfur (+6), <u>is reduced</u> by these

sulfate-reducing bacteria. The end product of sulfate reduction is hydrogen sulfide, H₂S, (oxidation number -2) an important natural product that participates in many biogeochemical processes. The H₂S they generate is responsible for the pungent smell (like that of rotten eggs) often encountered near coastal ecosystems. When sulfate-reducing bacteria grow, the H₂S formed from SO₄ ²⁻ reduction combines with the ferrous iron to form black, insoluble ferrous sulfide, which is not toxic. This is important for the conservation of the environment.

b) The net ionic equation under acidic conditions is:

              4 H₂ + SO₄²⁻ + H⁺ → HS⁻ + 4 H₂O

    Global reaction:  SO₄²⁻ + 2H⁺ → H₂S + O₂

3 0
3 years ago
A certain ore is 24.3% nickel by mass. how many kilograms of this ore would you need to dig up to have 55.0 g of nickel?
zysi [14]
Let x be the mass of the ore in grams such that the equation that would allow us to answer this item would be,

                     55 = (x)(0.243)

The value of x is calculated as,

                 x = 55/0.243
                   x = 226.337 grams

Then, solve for amount in kilograms by dividing the calculated value by 1000. This methodology will give us an answer of 0.226337. Hence, the answer is 0.226. 


4 0
3 years ago
Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12
satela [25.4K]

Answer:

Only Organism Z is alive, and Organism X has been dead longer than Organism Y.

Explanation:

After the death of an organism, there is radioactive disintegration of C-14 allotrope of carbon, which increases the ratio of C-12 to C-14 in a dead organism as compared to a living organism.

7 0
3 years ago
If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em
erica [24]

Answer: Wavelength  associated with the fifth line is 397 nm

Explanation:

E=\frac{hc}{\lambda}

\lambda = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant =10973731.6m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2

\frac{1}{\lambda}=2.52\times 10^{6}m

\lambda}=3.97\times 10^{-7}m=397 nm      1nm=10^{-9}m

Thus wavelength λ associated with the fifth line is 397 nm

7 0
4 years ago
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