net ionic equation:
SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
Explanation:
We have the following chemical reaction:
H₂SO₄ (aq) + Ba(OH)₂ (aq) → BaSO₄ (s) + 2 H₂O (l)
Now we write the ionic equation:
2 H⁺ (aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2 OH⁻ (aq) → BaSO₄ (s) + 2 H⁺ + 2 OH⁻ (aq)
We remove the spectator ions to obtain the net ionic equation:
SO₄²⁻ (aq) + Ba²⁺ (aq) → BaSO₄ (s)
where we have:
(aq) - aqueous
(s) - solid
(l) - liquid
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net ionic equation
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higher Ka value= stronger acid
stronger acids have weaker conjugate bases, so the acid with the strongest conjugate base would be acetic acid
hybridization is defined as mixing up of the atomic orbital with nearly same energies according to linear combination of atomic orbitals. the orbitals formed are equal in energy and are called hybrid orbitals .
Answer:
0.83 g
Explanation:
Step 1: Write the balanced equation
Fe + CuSO₄ ⇒ Cu + FeSO₄
Step 2: Calculate the moles corresponding to 0.75 g of Fe
The molar mass of Fe is 55.85 g/mol.
Step 3: Calculate the moles of Cu produced from 0.013 moles of Fe
The molar ratio of Fe to Cu is 1:1. The moles of Cu produced are 1/1 × 0.013 mol = 0.013 mol.
Step 4: Calculate the mass corresponding to 0.013 moles of Cu
The molar mass of Cu is 63.55 g/mol.
Answer:
See explanation
Explanation:
Let us look at the reaction again;
Cr2O7 2- (aq) + H2O(l)⇄ 2CrO4 2-(aq) + 2H^+(aq)
When we add sodium hydroxide to the system as shown, the hydroxide ion removes the hydrogen ion thereby leaving a large concentration CrO4^2-(aq) in the system this causes the solution to turn green(equilibrium position shifts to the right).
The net ionic equation is;
OH^-(aq) + H^+(aq) ----> H2O(l)
The reaction;
OH^-(aq) + H^+(aq) ----> H2O(l) is exothermic hence, if the temperature of the system is increased, the equilibrium position will shift towards the left hand side and the solution turns orange.
