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2 years ago

How many grams of sodium are in 1.000 mole of sodium?

Chemistry

2 answers:

jolli1 [7]2 years ago

8 0

Answer:

Explanation:

How many atoms are in a 3.5 g sample of sodium (Na)? In this example, multiply the grams of Na by the conversion factor 1 mol Na/ 22.98 g Na, with 22.98g being the molar mass of one mole of Na, which then allows cancelation of grams, leaving moles of Na.

julia-pushkina [17]2 years ago

5 0

Answer:

ONE MOLE of any element has 6.023x1023 atoms of that element. Therefore 1 mole or 22.99 grams of Na = 6.023x1023 atoms of Na.

Explanation:

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What effect does salt have on a marshmallow?

Naily [24]

Answer:

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2 years ago

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2 years ago

Read 2 more answers

Calculate the molarity of an HCl solution if 23.88 mL of it reacts with 6.5287 grams of sodium carbonate (106 g/mol) according t

Ivanshal [37]

Answer:

5.158 mol/L

Explanation:

To find the molarity, you need to use the formula:

Molarity (M) = moles / volume (L)

You have been grams sodium carbonate. You need to (1) convert grams Na₂CO₃ to moles (via molar mass), then (2) convert moles Na₂CO₃ to moles HCl (via mole-to-mole ratio from equation), then (3) convert mL to L (by dividing by 1,000), and then (4) use the molarity equation.

Steps 1 - 2:

2 HCl + 1 Na₂CO₃ ----> 2 NaCl + H₂O + CO₂

6.5287 g Na₂CO₃ 1 mole 2 moles HCl
-------------------------- x ------------- x ------------------------- = 0.12318 mole HCl
106 g 1 mole Na₂CO₃

Step 3:

23.88 mL / 1,000 = 0.02388 L

Step 4:

Molarity = moles / volume

Molarity = 0.12318 mole / 0.02388 L

Molarity = 5.158 mole/L

**mole/L is equal to M**

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3 years ago

Given the equation representing a reversible reaction:which formula represents the h+ acceptor in the forward reaction?

AnnyKZ [126]

Question is incomplete. Complete question is attached below
.............................................................................................................................

Answer: Option A: HCO3-(aq.)

Reason:
From the reaction, it can be seen that following reaction occurs in forward direct

HCO3-(aq) + H2O(l) → H2CO3(aq) + OH-(aq)

In above forward reaction, HCO3- accepts proton from H2O to generate H2CO3. Thus, according to Lowry and Bronsted theory of acid-base, HCO3- is a base, while H2CO3 is a conjugate acid.

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