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3 years ago

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How many grams of sodium are in 1.000 mole of sodium?

2 answers:

jolli1 [7]3 years ago

8 0

Answer:

Explanation:

How many atoms are in a 3.5 g sample of sodium (Na)? In this example, multiply the grams of Na by the conversion factor 1 mol Na/ 22.98 g Na, with 22.98g being the molar mass of one mole of Na, which then allows cancelation of grams, leaving moles of Na.

julia-pushkina [17]3 years ago

5 0

Answer:

ONE MOLE of any element has 6.023x1023 atoms of that element. Therefore 1 mole or 22.99 grams of Na = 6.023x1023 atoms of Na.

Explanation:

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What is indirect evidence in science

hodyreva [135]

Definition of indirect evidence. : evidence that establishes immediately collateral facts from which the main fact may be inferred : circumstantial evidence.

8 0

3 years ago

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

3 years ago

sorry that answer is wrong. A chemical bond is the force that holds together the elements in a compound

olya-2409 [2.1K]

That is a true statement <span />

8 0

3 years ago

How much of a 10 M solution is needed to make 1 liter of all solution?

SashulF [63]

Answer:

b is the answer 1000ml

please mark me brainlist

4 0

3 years ago

State the location and the total charge of the protons in a Ni-64 atom.

blsea [12.9K]

Location = nucleus ,
and you can see the total charge on the number that written below the substance, which would be 28+

hope this helps

6 0

3 years ago

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