All categories

7 months ago

What is the sum of 4 and its addictive inverse

Mathematics

1 answer:

Stolb23 [73]7 months ago

5 0

Answer:

Explanation:

Given the value of a variable x, the additive inversee will be its negative value.

Hence the additive inverse of x is -x

For a value of 4, then its additive inverse is -4

Taking the sum of 4 and its additive inverse, we will have;

= 4 + (-4)

= 4 - 4

= 0

Hence the sum of 4 and its additive inverse is 0

You might be interested in

What is the geometric sequence?<br><br> 2,3,4.5?

kykrilka [37]

An=a12n-1 or an=(1)2n-1

7 0

3 years ago

This is taking forever to find out

frosja888 [35]

Answer:

What is

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Pls help help help help help help help

Nutka1998 [239]

Answer:

y=-2x+5

Step-by-step explanation:

slope is going down 2 over 1

y-int is 5

8 0

2 years ago

Rose Betty and Cindy equally shared five boxes of crayons write an equation to show how much each girl got??

melomori [17]

5 divided by 3 is .6. I hope this makes sense. Good luck. I apologize if this is wrong

3 0

2 years ago

Evaluate the series

dalvyx [7]

Answer:

the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

C) 59

Step-by-step explanation:

Recall that;

$\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\$

Therefore, we can evaluate the series;

$\sum_{k=1}^{6}(25-k^2)$

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

$\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\$

So, the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

6 0

3 years ago