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1 year ago

What is the sum of 4 and its addictive inverse

Mathematics

1 answer:

Stolb23 [73]1 year ago

5 0

Answer:

Explanation:

Given the value of a variable x, the additive inversee will be its negative value.

Hence the additive inverse of x is -x

For a value of 4, then its additive inverse is -4

Taking the sum of 4 and its additive inverse, we will have;

= 4 + (-4)

= 4 - 4

= 0

Hence the sum of 4 and its additive inverse is 0

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If a car travels 172 miles in 4 hours how long will it take to travel 387 miles

Contact [7]

172/387 = 4/t

Let t = time to travel 387 miles

172t = 4(387)

172t = 1548

t = 1548/172

t = 9

Answer: 9 hours

4 0

3 years ago

Point M is the midpoint of AB¯¯¯¯¯¯¯¯. Find the length of AB¯¯¯¯¯¯¯¯.

alina1380 [7]

Answer:

AB = 142

Step-by-step explanation:

If M is the midpoint, then AM = MB

6x+5 = 7x -6

Subtract 6x from each side

6x-6x+5 = 7x-6x -6

5 = x-6

Add 6 to each side

5+6 = x-6+6

11=x

We want to find AB

AB = 6x+5+7x-6

AB = 13x -1

= 13(11) -1

=143-1

= 142

6 0

3 years ago

Find a unit vector in the same direction as the given vector: v = −14.5i + 2.5 j.

Elis [28]

ANSWER

$- \frac{29}{866} \sqrt{866} i + \frac{5}{866} \sqrt{866} j$

EXPLANATION

The given vector is v = −14.5i + 2.5 j.

The magnitude of this vector is

$|v| = \sqrt{ {( - 14.5)}^{2} + {2.5}^{2} }$

$v| = \sqrt{ {( - 14.5)}^{2} + {2.5}^{2} }$

$v| = \sqrt{ 216.5} = \frac{ \sqrt{866} }{2}$

The unit vector in the direction of this vector is

$= \frac{v}{ |v| }$

$= - \frac{14.5}{ \frac{ \sqrt{866} }{2} } i + \frac{2.5}{ \frac{ \sqrt{866} }{2} } j$

$= - \frac{29}{866} \sqrt{866} i + \frac{5}{866} \sqrt{866} j$

7 0

3 years ago

3y-y+8-2=20<br> combine like terms and solve

Flauer [41]

3y - y + 8 - 2 = 20
3y - y = 2y
8 - 2 = 6
2y + 6 = 20
2y = 20 - 6
y = 10 - 3
the answer is: y = 7

4 0

3 years ago

Two mechanics worked on a car. The first mechanic charged $115 per hour, and the second mechanic charged $50 per hour. The mecha

anygoal [31]

115*20=2300.
50*5=250

First mechanic 20 hours
Second mechanic 5 hours

8 0

3 years ago