Use the eq. of Young modulus Y=(F/A)/(∆l/lo)
dimana ∆l is the elongation of wire, lo is its initial length.
So ∆l = (F/A)lo/Y.
∆l = (1000N/(6.5 × 10^-7 m^2))×(2.5m)/(2.0 × 10^-11 N/m^2)
Use calculator to finish it.
Answer:
7808 m/s
Explanation:
Find NE velocity after 60 s of acceleration in that direction:
= a t = 28.4 m/s^2 * 60 s = 1704 m/s
Vertical component = 1704 sin 45 = 1204.9 m/s
Horiz component = 1704 cos 45 = 1204.9 m/s
Add the two vertical components
6510 + 1204.9 = 7714.9 m/s = vertical velocity
Pythagorean theorem to find resultant of vertical and horiz v's
Vf ^2 = 1204.9^2 + 7714.9^2 0
Vf = 7808. m/s
Answer:
Explanation:
α = (ωf - ωi)/t
acceleration phase
ωf = 132 rev/min (2π rad/rev / 60 s/min) = 4.4π rad/s
α₁ = (4.4π - 0)/20 = 0.22π rad/s²
α₂ = (0 - 4.4π)/40 = - 0.11π rad/s²
α₁/α₂ = 0.22π/- 0.11π = -2
To solve this, we
use the formula:
y = v0 t + 0.5 a t^2
where y is distance, v0 is initial velocity, t is time
and a is acceleration
Since we know that total time is 8.5 seconds, hence going
up must be 4.25 s and going down is 4.25 s.
a = 0.379 g = 0.379 (9.8 m/s^2) = 3.7142 m/s^2
going up:
y = v0 (4.25) - 0.5 (3.7142) (4.25)^2
y = 4.25 v0 – 33.5439 -->
eqtn 1
going down:
y = 0 (4.25) + 0.5 (3.7142) (4.25)^2
y = 33.5439
y = 33.5439 m
Calculating for v0 from equation 1:
33.5439 = 4.25 v0 – 33.5439
4.25 v0 = 67.0877
v0 = 15.78535 m/s
answers:
a. y = 33.5439 m
b. v0 = 15.78535 m/s
c.
Answer:
a. 6.41 m/s
b. 120.85 m/s^2
Explanation:
The computation is shown below:
a. Pebble speed is
As we know that according to the tangential speed,


= 6.41 m/s
The 18.84 come from

= 18.84
b. The pebble acceleration is


= 120.85 m/s^2
We simply applied the above formulas so that the pebble speed and the pebble acceleration could come and the same is to be considered