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Elodia [21]
3 years ago
13

Radio waves of frequency 1.667 GHzGHz arrive at two telescopes that are connected by a computer to perform interferometry. One p

ortion of the same wave front travels 1.260 mm farther than the other before the two signals are combined.
Required:
a. Will the two waves combine constructively or destructively?
b. Calculate the value of m for the path difference between the two signals
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Explanation:

The frequency of radio waves is 1.667 GHz

One portion of the same wave front travels 1.260 mm farther than the other before the two signals are combined.

There are two conditions for interference either constructive or destructive.

For constructive interference , the path difference is n times of wavelength and for destructive interference, the path difference is (n+1/2) times of wavelength

We can find wavelength in this case as follows :

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{1.667\times 10^9}\\\\\lambda=0.1799\ m

If we divide path difference by wavelength,

\dfrac{\delta}{\lambda} =\dfrac{1.26}{0.1799}\\\\\dfrac{\delta}{\lambda} =7\\\\\delta =7\lambda

It means that the path difference is 7 times of the wavelength. it means the two waves combine constructively and the value of m for the path difference between the two signals is 7.

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makvit [3.9K]
Use the eq. of Young modulus Y=(F/A)/(∆l/lo)
dimana ∆l is the elongation of wire, lo is its initial length.
So ∆l = (F/A)lo/Y.
∆l = (1000N/(6.5 × 10^-7 m^2))×(2.5m)/(2.0 × 10^-11 N/m^2)
Use calculator to finish it.
5 0
3 years ago
A space shuttle is flying north at 6,510 m/s. It
Maksim231197 [3]

Answer:

7808 m/s

Explanation:

Find NE velocity after 60 s  of acceleration in that direction:

  = a t  =  28.4 m/s^2 * 60 s = 1704  m/s

    Vertical component = 1704 sin 45 = 1204.9 m/s

     Horiz component = 1704 cos 45 = 1204.9  m/s

Add the two vertical components

  6510 + 1204.9 = 7714.9 m/s = vertical velocity

Pythagorean theorem to find resultant of vertical and horiz  v's

Vf ^2 = 1204.9^2   + 7714.9^2 0

Vf = 7808. m/s

7 0
2 years ago
A ceiling fan is turned on and reaches an angular speed of 132 rev/min in 20 s. It is then turned off and coasts to a stop in an
Mkey [24]

Answer:

Explanation:

α = (ωf - ωi)/t

acceleration phase

ωf = 132 rev/min (2π rad/rev / 60 s/min) = 4.4π rad/s

α₁ = (4.4π - 0)/20 = 0.22π rad/s²

α₂ = (0 - 4.4π)/40 = - 0.11π rad/s²

α₁/α₂ = 0.22π/- 0.11π = -2

8 0
2 years ago
A tennis ball on mars, where the acceleration due to gravity is 0.379g and air resistance is negligible, is hit directly upward
Studentka2010 [4]

 To solve this, we use the formula:

y = v0 t + 0.5 a t^2

where y is distance, v0 is initial velocity, t is time and a is acceleration

 

Since we know that total time is 8.5 seconds, hence going up must be 4.25 s and going down is 4.25 s.

a = 0.379 g = 0.379 (9.8 m/s^2) = 3.7142 m/s^2

 

going up:

y = v0 (4.25) - 0.5 (3.7142) (4.25)^2

y = 4.25 v0 – 33.5439                       --> eqtn 1

 

going down:

y = 0 (4.25) + 0.5 (3.7142) (4.25)^2

y = 33.5439

y = 33.5439 m

 

Calculating for v0 from equation 1:

33.5439 = 4.25 v0 – 33.5439

4.25 v0 = 67.0877

v0 = 15.78535 m/s

 

answers:

a. y = 33.5439 m

b. v0 = 15.78535 m/s

c.

8 0
2 years ago
Your roommate is working on his bicycle and has the bike upside down. He spins the 68.0 cm -diameter wheel, and you notice that
MAVERICK [17]

Answer:

a. 6.41 m/s

b. 120.85 m/s^2

Explanation:

The computation is shown below:

a. Pebble speed is

As we know that according to the tangential speed,

v = r \times \omega

= \frac{0.68}{2} \times  18.84

= 6.41 m/s

The 18.84 come from

=  2 \times 3.14 \times 3

= 18.84

b. The pebble acceleration is

a = \frac{v^2}{r}

= \frac{6.41^2}{0.34}

= 120.85 m/s^2

We simply applied the above formulas so that the pebble speed and the pebble acceleration could come and the same is to be considered

3 0
3 years ago
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