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MArishka [77]
2 years ago
12

HELP!!!!!! Need Help !!!

Physics
1 answer:
denis23 [38]2 years ago
3 0

Answer:

its y

Explanation:

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I got 5,225 by 50x4.18= 209(25)=5,225
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How do the most common forms of energy work?
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activity 2

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Helppp!!! what's the answer to this??
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(b)

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The voltage always lags the current by 90°, regardless of the frequency.

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Astronomers discover an exoplanet, a planet obriting a star other than the Sun, that has an orbital period of 3.27 Earth years i
Naddik [55]

Answer:

  r = 3.787 10¹¹ m

Explanation:

We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration

    F = ma

    G m M / r² = m a

The centripetal acceleration is given by

    a = v² / r

For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship

    v = d / t

The distance traveled Esla orbits, in a circle the distance is

    d = 2 π r

Time in time to complete the orbit, called period

     v = 2π r / T

Let's replace

    G m M / r² = m a

    G M / r² = (2π r / T)² / r

    G M / r² = 4π² r / T²

    G M T² = 4π² r3

     r = ∛ (G M T² / 4π²)

Let's reduce the magnitudes to the SI system

     T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)

     T = 1.03 10⁸ s

Let's calculate

      r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]

      r = ∛ (21.44 10³⁵ / 39.478)

      r = ∛(0.0543087 10 36)

      r = 0.3787 10¹² m

      r = 3.787 10¹¹ m

7 0
3 years ago
A football is kicked from ground level at an angle of 53 degrees. It reaches a maximum height of 7.8 meters before returning to
Nonamiya [84]

Answer:

1.61 second

Explanation:

Angle of projection, θ = 53°

maximum height, H = 7.8 m

Let T be the time taken by the ball to travel into air. It is called time of flight.

Let u be the velocity of projection.

The formula for maximum height is given by

H = \frac{u^{2}Sin^{2}\theta }{2g}

By substituting the values, we get

7.8= \frac{u^{2}Sin^{2}53 }{2\times 9.8}

u = 9.88 m/s

Use the formula for time of flight

T = \frac{2uSin\theta }{g}

T = \frac{2\times 9.88\times Sin53 }{9.8}

T = 1.61 second

7 0
2 years ago
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