1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brrunno [24]
3 years ago
14

How can eclipsing binary stars be identified?

Physics
1 answer:
Leviafan [203]3 years ago
3 0
D) they become dimmer at regular intervals.
You might be interested in
A quarter is tossed up from the roof of a skyscraper and hits the sidewalk below. Which of the following graphs best shows the v
laila [671]

Answer:

pic

Explanation:

5 0
2 years ago
What does hydraulic mean?
Harrizon [31]

Answer:

denoting, relating to, or operated by a liquid moving in a confined space under pressure.

4 0
2 years ago
A car moving with an initial speed of 25 m/s slows down to a speed of 5 m/s in 10 seconds Calculate a) the acceleration of the c
stealth61 [152]

Answer :

(a) The acceleration  of the car is, -2m/s^2

(b) The distance covered by the car is, 150 m

Explanation :  

By the 1st equation of motion,

v=u+at ...........(1)

where,

v = final velocity = 5 m/s

u = initial velocity  = 25 m/s

t = time = 10 s

a = acceleration  of the car = ?

Now put all the given values in the above equation 1, we get:

5m/s=25m/s+a\times (10s)

a=-2m/s^2

The acceleration  of the car is, -2m/s^2

By the 2nd equation of motion,

s=ut+\frac{1}{2}at^2 ...........(2)

where,

s = distance covered by the car = ?

u = initial velocity  = 25 m/s

t = time = 10 s

a = acceleration  of the car = -2m/s^2

Now put all the given values in the above equation 2, we get:

s=(25m/s)\times (10s)+\frac{1}{2}\times (-2m/s^2)\times (10s)^2

By solving the term, we get:

s=150m

The distance covered by the car is, 150 m

8 0
3 years ago
A girl and a boy are riding on a merry go round that is turning at a constant rate. The girl is near the outer edge, and the boy
galina1969 [7]

Answer:

The girl has greater tangential acceleration

Explanation:

The angular acceleration (\alpha) of the merry go round is equal to the rate of the change of the angular velocity, \omega:

\alpha = \frac{d\omega}{dt}

Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.

The tangential acceleration instead is given by

a_t = \alpha r

where

\alpha is the angular acceleration

r is the distance from the centre of the merry go round

Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

5 0
3 years ago
14. The average speed of a car was 60 m/s by the time it reached the finish line. The car moved in a straight line and traveled
Leni [432]
7.5m. Have a good day :)
4 0
3 years ago
Other questions:
  • Explain how a parachute works
    11·2 answers
  • What is the law that states that matter can not be created nor destroyed?
    13·1 answer
  • What might cause matter to change states
    11·1 answer
  • A student of mass 63.4 kg, starting at rest, slides down a slide 21.2 m long, tilted at an angle of 26.1° with respect to thehor
    11·1 answer
  • How is temperature and viscosity related?
    10·1 answer
  • A car on a Ferris wheel has an angular displacement of π 4 rad, which corresponds to an arc length of 28.2 m. What is the Ferris
    11·1 answer
  • Which term , when multiplied by mass, equals density ?
    5·2 answers
  • A car travels at 90 km per hour how much distance in metre does the car travel in 25 seconds​
    14·1 answer
  • Which list contains only vector quantities?
    11·1 answer
  • The wave function for a traveling wave on a taut string is (in SI units)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!