Two large blocks of wood are sliding towards each other on the frictionless surface of a frozen pond. The blocks collide head-on. Then the decrease in total kinetic energy after the collision is 13.18 J.
From the law of conservation of linear momentum, we know, Pi = Pf
where, Pi is total initial momentum
Pf is total final momentum
m₁u₁ + m₂u₂ = M₁V₁ + M₂V₂
4*2 + 6*(-2.5) = 4* V₁ + 6*(0.5)
4V₁ = 8 - 15 -3
V₁ = -2.5 m/s
Now, let us calculate the initial and final kinetic energies.
The formula to find out kinetic energy is K.E = 1/2 mv²
Initial kinetic energy = 1/2* 4* 2² + 1/2* 6* (-2.5)² = 26.75 J
Final kinetic energy = 1/2* 4* 2.5² + 1/2* 6* (-0.5)² = 13.57 J
The difference in total kinetic energy is K₂ - K₁ = (13.57 - 26.75) = -13.18 J
Thus, the decrease in total kinetic energy of the given blocks after collision is 13.18 J.
To know more about kinetic energy:
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