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podryga [215]
3 years ago
9

Help me If you answered this, you will have 30 points :)

Physics
1 answer:
trapecia [35]3 years ago
3 0

Answer:

the lever for location 1 is

dropping water into ladle

Explanation:

i dont know if i have the question answer right though if so let me know

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If it takes 20n to move a box, how much power will be needed to move the box a diatance
solmaris [256]

The power applied to move the box anywhere is

   (20 n) x (distance moved) / (time to move the distance) .
 
3 0
3 years ago
The metal wire in an incandescent lightbulb glows when the lights is switch on and stops glowing when switched off. This simple
lutik1710 [3]

Answer:

When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat.  

Explanation:

4 0
3 years ago
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A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on
Nutka1998 [239]

Answer:

60N

Explanation:

in this case the minimum amount of force required must be equal to the friction Force. i.e <u>Newton</u><u>'s</u><u> </u><u>first</u><u> </u><u>law</u><u> of</u><u> </u><u>mot</u><u>ion</u><u>.</u>

therefore the maximum amount of frictional force is equal to the applied force which is 60N.

because of the net force acting on the object is zero the object is in constant motion . i.e equal and opposite force must be applied so that the object is in constant velocity therefore the total frictional force must be 60N

8 0
4 years ago
What's the name of the compound Kl?
Nat2105 [25]

Answer: Potassium iodide

Explanation: their you go

3 0
2 years ago
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Automobiles must be able to sustain a frontal impacl The automobile design must allow low speed impacts with little sustained da
valentinak56 [21]

Answer: the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

Explanation:

Given that;

mass of vehicle m = 1000 kg

for a low speed test; V = 2.5 m/s

bumper maximum deflection = 4 cm = 0.04 m

First we determine the energy of the vehicle just prior to impact;

W_v = 1/2mv²

we substitute

W_v = 1/2 × 1000 × (2.5)²

W_v = 3125 J

now, the the effective design stiffness k will be:

at the impact point, energy of the vehicle converts to elastic potential energy of the bumper;

hence;

W_v = 1/2kx²

we substitute

3125 = 1/2 × k (0.04)²

3125 = 0.0008k

k = 3125 / 0.0008

k = 3906250 N/m

Therefore, the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm is 3906250 N/m

3 0
3 years ago
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