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KiRa [710]
3 years ago
10

Please help me on this I know it’s not B this stuff is kinda hard for me

Physics
1 answer:
Liula [17]3 years ago
7 0

There you go again.  Newton's 3rd Law says "for every action there is an EQUAL OPPOSITE reaction.".

<u><em>EQUAL</em></u><em> </em>and <u><em>OPPOSITE</em></u>

If THIS MUCH force pushes the bullet THAT way, then THE SAME amount of force pushes the rifle THIS way.

The bullet pushes backward on the rifle with the <u>same</u> amount of force as the rifle exerts on the bullet.

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luda_lava [24]

Answer:

When a body is placed on a table top, it exerts a force equal to its weight downwards on the table top but does not move or fall. (i) Name the force exerted ...

5 0
3 years ago
Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
nikdorinn [45]

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

P=60+100\\P=160 [W]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

P=V*I

where:

P = power [W]

V = voltage [V]

I = current [amp]

I = P/V\\I=160/240\\I=0.67 [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

V=I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R

60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

R = 133.66 + 225\\R = 358.67 [ohms]

7 0
3 years ago
Do you have to take physics to graduate high school?
Lina20 [59]
Usually, you have to take two years of physical sciences with lab. It doesn't have to be physics, it can be chemistry or biology. 
6 0
3 years ago
What mass of a material with density rho is required to make a hollow spherical shell having inner radius r1 and outer radius r2
Margarita [4]

Answer:

m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3  )

Explanation:

  • We have to make a hollow sphere of inner  radius r_1 and outer radius r_2.

Then the mass of the material required to make such a sphere would be calculated as:

Total volume of the spherical shell:

V_t=\frac{4}{3} \pi.r_2^3

And the volume of the hollow space in the sphere:

V_h=\frac{4}{3} \pi.r_1^3

Therefore the net volume of material required to make the sphere:

V=V_t-V_h

V=\frac{4}{3} \pi(r_2^3-r_1^3)

  • Now let the density of the of the material be \rho.

<u>Then the mass of the material used is:</u>

m=\rho.V

m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3  )

4 0
4 years ago
The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b
bagirrra123 [75]

To solve this problem it is necessary to address the concepts related to Torque as a function of the force and distance where it is applied and the moment of inertia from which the torque, moment of inertia and angular acceleration are related.

By definition the torque is defined as

\tau = F*r

Where,

\tau = Torque

F = Force

r = Radius

For our values we have:

\tau = F*r

\tau = (1.75*10^3)(2.8*10^{-2})

\tau = 49Nm

Consequently the calculation of the moment of inertia would then be given by the relationship

\tau = I\alpha

I=\frac{\tau}{\alpha}

Replacing with our values

I = \frac{49}{150}

I = 0.322Kg.m^2

The moment of inertia of the boxer's forearm 0.322Kg.m^2

4 0
3 years ago
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