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KiRa [710]
3 years ago
10

Please help me on this I know it’s not B this stuff is kinda hard for me

Physics
1 answer:
Liula [17]3 years ago
7 0

There you go again.  Newton's 3rd Law says "for every action there is an EQUAL OPPOSITE reaction.".

<u><em>EQUAL</em></u><em> </em>and <u><em>OPPOSITE</em></u>

If THIS MUCH force pushes the bullet THAT way, then THE SAME amount of force pushes the rifle THIS way.

The bullet pushes backward on the rifle with the <u>same</u> amount of force as the rifle exerts on the bullet.

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A car starts from rest and after 10 seconds is traveling at 20 m/s. Assuming that it continues to accelerate at the same rate it
Alenkinab [10]

Assuming that it continues to accelerate at the same rate it will take another 10 seconds to reach 40 m/s.

Answer:

Explanation:

Since the first question states that there is a change in the velocity from rest to 20 m/s in 10 seconds time interval. So the acceleration experienced by the car during this 10 seconds should be determined first as follows:

Acceleration = (final velocity-initial velocity)/Time

Acceleration = (20-0)/10 = 2 m/s².

So this means the car is traveling with an acceleration of 2 m/s².

As it is stated that the car continues to move with same acceleration, then in the second case, the acceleration is fixed as 2 m/s², initial velocity as 20 m/s and final velocity as 40 m/s. So the time taken for the car to reach this velocity with the constant acceleration value will be as follows:

Time = Change in velocity/Acceleration

Time = (40-20)/2 = 20/2=10 s

So again in another 10 seconds by the car to reach 40 m/s from 20 m/s. Similarly the car will take a total of 20 seconds to reach from rest to 40 m/s value for velocity.

5 0
3 years ago
Que capacidade física consiste em deslocar o corpo no espaço o mais rápido possível, mudando o centro de gravidade de posição, s
grin007 [14]

Answer:ur mom

Explanation:because

6 0
3 years ago
I need help plzzz!!!!!
Masteriza [31]

Answer:

I truly don't know

Explanation:

5 0
4 years ago
You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,
g100num [7]

Answer:

T = 29.66 ^o C

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

ms \Delta T = m' L

so here we have

0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)

T = \frac{2512.5}{0.220 \times 385}

T = 29.66 ^o C

5 0
3 years ago
Calculate the amount of air in a room 6m long, 5m wide and 3mm high.​
sattari [20]

Answer:

0.09kg of air

Explanation:

The dimensions of the room are given

change the height to meters by dividing it by thousand.

For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).

Volume refers to the amount of space inside a box or a object.

The amount of air is equal to the volume.

6 0
2 years ago
Read 2 more answers
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