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2 years ago

Which graph below represents how the velocity of the sphere changes over time when falling with constant acceleration?

Physics

1 answer:

Amiraneli [1.4K]2 years ago

4 0

Graph B represents the velocity of the sphere changes over time when falling with constant acceleration.

Acceleration is the measure of how quickly a body's velocity varies with regard to time, and constant acceleration occurs when a body's velocity changes proportionately over a period of time, or at a constant rate. It measures in m/s2.

It is claimed that a body has continual positive acceleration when it begins to move with an initial velocity of zero and gradually increases to a positive value over time.

Constant positive acceleration is demonstrated by a ball falling freely in a vertical direction.

To know more about constant acceleration. visit : brainly.com/question/9754169

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An automobile with a mass of 1180 kg is traveling at a speed v = [06] ____________________ m/s. a. What is its kinetic energy in

iogann1982 [59]

Complete Question:

An automobile with a mass of 1180 kg is traveling at a speed v =2.51 m/s. What is its kinetic energy in SI units? What speed (m/s) must an 82.7-kg person move to have the same kinetic energy? At what speed (m/s) must is 12.1-g bullet move to have the same kinetic energy? What would be the speed (m/s) of the automobile if its kinetic energy were doubled?

Answer:

a) 3717.1 J b) 9.48 m/s c) 783.8 m/s d) 3.55 m/s

Explanation:

By definition, the kinetic energy of a mass m with a speed v, is as follows:

$K = \frac{1}{2} * m *v^{2}$

if m= 1180 Kg, and v= 2.51 m/s, the kinetic energy can be calculated as follows:

$K = \frac{1}{2} * m *v^{2} = \frac{1}{2} * 1180 kg*(2.51 m/s)^{2} = 3717.1 J$

If the kinetic energy must be the same, and m= 82,7 Kg, we can write the following expression:

$K = \frac{1}{2} * m *v^{2} = \frac{1}{2} * 82.7 kg*((v)(m/s))^{2} = 3717.1 J$

We can solve the above equation as follows:

$v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{82.7kg} } = 9.48 m/s$

If K remains the same, and m = 12.1 g = 0.0121 kg (in SI units). we can solve for v as follows:

$v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{0.0121kg} } = 783.8 m/s$

Now, if the kinetic energy were doubled, we would have the following equation:

$K = \frac{1}{2} * m *v^{2} = \frac{1}{2} * 1180 kg*((v) m/s)^{2} = 3717.1 J * 2 = 7434.2 J$

We can solve for the new speed v as follows:

$v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*7434.2J}{1180kg} } = 3.55 m/s$

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) A neutral pion with rest mass 135MeV /c2 is traveling with speed 0.5c as measured in a lab. The pion then decays into two phot

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Explanation:

Detailed explanation and calculation is shown in the image below

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