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givi [52]
4 years ago
7

Jessica took a mylar balloon outside on a very cold day. As she waited for the bus the balloon began to shrink. What is the best

explanation of this?
Physics
1 answer:
marin [14]4 years ago
7 0
As she filled the balloon up with air, the air, let’s say, was at room temperature and therefore was able to expand and fill the balloon. When air inside of the balloon was exposed to the cold air. The air molecules started to contract or come closer together. This causes the air to fill less area inside of the balloon and therefore making the balloon smaller.
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Suppose you are testing the buoyancy of different objects. Study the table and choose the object with the greatest buoyant force
Butoxors [25]
According to Archimedes Principle, Buoyant Force is equivalent to the displaced<span> amount of </span><span>fluid, So, Larger the amount of water displaced, more the Buoyant force will be.

In short, Object 3 would have the largest Buoyant Force

Hope this helps!</span>
7 0
3 years ago
Read 2 more answers
What is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2m/s
vlada-n [284]

Answer:

<h2>14.52 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 7.26 \times  {2}^{2}  \\  = 2 \times 7.26

We have the final answer as

<h3>14.52 J</h3>

Hope this helps you

4 0
3 years ago
The total number of stars in the observable universe is roughly equivalent to:
musickatia [10]

Answer:

The number of grains of sand on all the beaches on Earth

Explanation:

if we assume grain of sand has an average size , then the number of grains of sand on all the beaches on Earth is roughly 7.5 \times 10^{18}

The total number of stars in the observable universe is roughly equivalent to 1 billion trillion. which is roughly  equal to the number of grains of sand on all the beaches on Earth.

3 0
3 years ago
The largest and the smallest balls used in the experiment are with diameter 9.52 mm, and 2.38 mm respectively. For a glycerin wi
svlad2 [7]

Answer

given,

largest diameter of  balls = 9.52 mm = 0.00476 m

                                 radius = 0.00476

smallest diameter of ball = 2.38 mm = 0.00238 m

                                 radius = 0.00119

viscosity = 1.5 Pa.s

density of the ball = 1.42 g/cm

F = 6\pi \eta r V_t

F = \dfrac{mv}{t}

F = \dfrac{\dfrac{4}{3}\pi\ r^3\times (\rho-\sigma) \times 0.99 V_T}{t}

6\pi \eta r V_t = \dfrac{\dfrac{4}{3}\pi\ r^3\times rho \times 0.99 V_T}{t}

t = \dfrac{\dfrac{4}{3}\pi\ r^3\times rho \times 0.99 V_T}{6\pi \eta r V_t}

t= \dfrac{0.22 r^2 (\rho-\sigma) }{\eta}

for small balls

t= \dfrac{0.22\times 0.00119^2 (1460-1300)}{1.5}

t = 0.033 ms

for larger ball

t= \dfrac{0.22\times 0.00476^2 (1460-1300)}{1.5}

t = 0.531 ms

6 0
4 years ago
Matt is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his spe
Olin [163]

(150 meters) / (18 seconds) = 8.33 meters per second

4 0
3 years ago
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