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3 years ago

What is the first sing of dehydration

Physics

2 answers:

Maksim231197 [3]3 years ago

8 0

Dark yellow pee ( have a blessed day )

Elodia [21]3 years ago

6 0

Answer:Two early signs of dehydration are thirst and dark-coloured urine. This is the body's way of trying to increase water intake and decrease water loss.

Explanation:

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How many nuclei decay in one half life?

Archy [21]

Answer:

50%

Explanation:

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3 years ago

Read 2 more answers

How far will an object move in 6 s if its average

Dafna11 [192]

Given:-

Time taken by the particle (t) = 6 s
Average speed (v) = 40 m/s

To Find: Distance (s) travelled by the particle.

We know,

s = vt

where,

s = Distance travelled,
v = Speed &
t = Time taken.

Putting the values,

s = (40 m/s)(6 s)

→ s = 240 m ...(Ans.)

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3 years ago

#1 How fast does an object need to travel to stay in orbit for one second?

fenix001 [56]

19685 mph to stay in orbit or 8 kilometers per second to stay in orbit if this dose not help tell me

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3 years ago

Imagine you re in an entrepreneur and have been provided a loan by a bank to set up a small electro plating unit. What would you

Lena [83]

Answer:

Electroplating involves deposition of a thin layer of metal onto the surface of a substance(compound) through electric current. This helps preserve the substance(compound) from rust and oxidative damage.

As an entrepreneur which has been provided a loan by a bank to set up a small electro plating unit. I would venture into electroplating electronic/electric appliances parts.This is because these types of appliances are in vogue now and used my millions of people for their day to day activities. This means that more people will come for various degrees of production and repairs which would include electroplating . This translates to more customers and more money for the repayment of the loan.

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3 years ago

A 0.80-μm-diameter oil droplet is observed between two parallel electrodes spaced 11 mm apart. The droplet hangs motionless if t

Arisa [49]

A) $2.4\cdot 10^{-16}kg$

The radius of the oil droplet is half of its diameter:

$r=\frac{d}{2}=\frac{0.80 \mu m}{2}=0.40 \mu m = 0.4\cdot 10^{-6}m$

Assuming the droplet is spherical, its volume is given by

$V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (0.4\cdot 10^{-6} m)^3=2.68\cdot 10^{-19} m^3$

The density of the droplet is

$\rho=885 kg/m^3$

Therefore, the mass of the droplet is equal to the product between volume and density:

$m=\rho V=(885 kg/m^3)(2.68\cdot 10^{-19} m^3)=2.4\cdot 10^{-16}kg$

B) $1.5\cdot 10^{-18}C$

The potential difference across the electrodes is

$V=17.8 V$

and the distance between the plates is

$d=11 mm=0.011 m$

So the electric field between the electrodes is

$E=\frac{V}{d}=\frac{17.8 V}{0.011 m}=1618.2 V/m$

The droplet hangs motionless between the electrodes if the electric force on it is equal to the weight of the droplet:

$qE=mg$

So, from this equation, we can find the charge of the droplet:

$q=\frac{mg}{E}=\frac{(2.4\cdot 10^{-16}kg)(9.81 m/s^2)}{1618.2 V/m}=1.5\cdot 10^{-18}C$

C) Surplus of 9 electrons

The droplet is hanging near the upper electrode, which is positive: since unlike charges attract each other, the droplet must be negatively charged. So the real charge on the droplet is

$q=-1.5\cdot 10^{-18}C$

we can think this charge has made of N excess electrons, so the net charge is given by

$q=Ne$

where

$e=-1.6\cdot 10^{-19}C$ is the charge of each electron

Re-arranging the equation for N, we find:

$N=\frac{q}{e}=\frac{-1.5\cdot 10^{-18}C}{-1.6\cdot 10^{-19}C}=9.4 \sim 9$

so, a surplus of 9 electrons.

3 0

4 years ago