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3 years ago

What is the first sing of dehydration

Physics

2 answers:

Maksim231197 [3]3 years ago

8 0

Dark yellow pee ( have a blessed day )

Elodia [21]3 years ago

6 0

Answer:Two early signs of dehydration are thirst and dark-coloured urine. This is the body's way of trying to increase water intake and decrease water loss.

Explanation:

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Resistors labeled 100 Ω have true resistances that are between 80 Ω and 120 Ω. Let X be the mass of a randomly chosen resistor.

STatiana [176]

Answer:

See explanation for step by step explanations.

Explanation:

Let X be the mass of a randomly selected resistor

The probability density function is given as

, 80<x<120

=0, otherwise

a) By using the given pdf we have to find the probability of the resistors having resistance less than 90

=0.0625

the probability of the resistors having resistance less than 90 is 0.0625

Step 2 of 4<

/p>

b) we have to find the mean resistance

Mean=

=106.67

The mean resistance is 106.67

5 0

3 years ago

A box is sliding down an incline tilted at a 16.0 angle above horizontal. The box is initially sliding down the incline at a spe

blsea [12.9K]

Answer:

d) 1.44m

Explanation:

According to Newton's second law:

$\sum F=m.a\\$

analyzing the horizontal components of the force:

$\sum F_x=mg*sin(\theta)-\µ*m.g*cos(\theta)\\\sum F_x=m*9.8*(sin(16^o)-0.420*cos(16^o))\\\sum F_x=-1.25m$

applying the second law

$-1.25m=m.a\\a=-1.25m/s^2$

given the acceleration we can calculate the distances traveled before stopping:

$(v_f)^2=(v_o)^2+2.a.\Delta x\\0=(1.90m/s)^2-2(1.25)*\Delta x\\\Delta x=1.44m$

8 0

3 years ago

An ultrasonic ruler, such as the one discussed in Example 4 in Section 16.6, displays the distance between the ruler and an obje

garik1379 [7]

Answer:

reading would be 5.413 m.

Explanation:

Given:-

- The actual distance from ruler to an object is d = 24.0 m

- The adiabatic bulk modulus, B = 2.37 *10^9 Pa

- The density of seawater, ρ = 1025 kg/m^3

- The preset value of speed of sound in air, v_th = 343 m/s.

Find:-

Determine the distance reading that the ruler displays.

Solution:-

- We will first determine the actual speed of the sound ( v_a) in sea-water which can be determined from the following formula:

v_a = √ (B / ρ )

- Plug in the values in the relationship above and compute v_a:

v_a = √ ( 2.37 *10^9 / 1025 )

v_a = 1520.59038 m/s

- The time taken (t) for for the sound to travel from source(ruler) to an object which is d distance away.

d = v_a*t

t = d / v_a

t = 24.0 / 1520.59038

t = 0.01578 s

- The distance reading on the ruler would be preset speed (v_th) of sound in air multiplied by the time taken(t).

reading = v_th*t

reading = (343)*(0.01578)

= 5.413 m

6 0

3 years ago

A ball is thrown at an angle of to the ground. If the ball lands 90 m away, what was the initial speed of the ball?

andre [41]

Answer:

The initial speed of the ball is 30 m/s.

Explanation:

It can be assumed that the ball is thrown at an angle of 45 degrees to the ground. The ball lands 90 m away. We need to find the initial speed of the ball. We know that the horizontal distance covered by the projectile is called its range. It is given by :

$R=\dfrac{u^2\ sin2\theta}{g}$

u is the initial speed of the ball.

$v=\sqrt{\dfrac{Rg}{sin2\theta}}$

$v=\sqrt{\dfrac{90\times 9.8}{sin2(45)}}$

v = 29.69 m/s

v = 30 m/s

So, the initial speed of the ball is 30 m/s. Hence, this is the required solution.

8 0

3 years ago

Two very quick questions!!

stepladder [879]

<span>The weight lifted by a machine to the applied force on a machine is called mechanical advantage. This is written as Mechanical advantage, M. A, = load(weight)/effort. So for 1) M.A = 2 and load = 2, 000lb = 8896.446N. So 2 = 8896.446/ effort Effort = 8896.446/2 = 4448.48 Similarly for M.A of 2, 000, 000 we have Effort = 8896.446/ 2, 000, 000 = 0.004448</span>

8 0

2 years ago

Read 2 more answers