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ahrayia [7]
3 years ago
11

How many moles of oxygen are required for the combustion of 35.5 g of Magnesium Mg+O2-->MgO Please balance

Chemistry
1 answer:
Verdich [7]3 years ago
6 0

Answer:

0.74 moles of oxygen are required for combustion

Explanation:

Given data:

Number of moles of oxygen required = ?

Mass of Mg = 35.5 g

Solution:

Chemical equation:

2Mg + O₂         →       2MgO

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 35.5 g/ 24 g/mol

Number of moles = 1.48 mol

Now we will compare the moles of Mg with oxygen.

                  Mg           :         O₂

                   2             :          1

                 1.48           :        1/2×1.48 = 0.74 mol

0.74 moles of oxygen are required for combustion.

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How many molecules of CF₂Cl₂ are in 45.7 grams of CF₂Cl₂? (Show work)
posledela

Answer:

The answer to your question is: 2.20 x 10 ²³ molecules

Explanation:

Data

mass = 45.7 g

molecules of CF₂Cl₂ = ?

Process

1.- Calculate the mass number of CF₂Cl₂

   C = 12    F =2 x 19    Cl = 2 x 35.5

   total = 12 + 38 + 71

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2.- Use the Avogradro's number to solve the problem

                       121 g -------------------  6.023 x 10²³ molecules of CF₂Cl₂

                        45.7 g ---------------     x

                        x = (45.7 x 6.023 x 10²³) / 121

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