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yanalaym [24]
3 years ago
10

The density of aluminum is 2.7 g/cm3. A metal sample has a mass of 52.0 grams and a volume of 17.1 cubic centimeters. Could the

sample be aluminum? EXPLAIN your answer.
Chemistry
1 answer:
nikklg [1K]3 years ago
5 0

Answer:

The given metal sample is not aluminum because its density is 3.0 g/cm³ while density of aluminum is  2.7 g/cm³.

Explanation:

Given data:

Density of aluminum = 2.7 g/cm³

Mass of metal sample = 52.0 g

Volume of metal sample = 17.1 cm³

which sample is that = ?

Solution:

The given problem will be solve through density formula.

d = m/v

d = density

m = mass

v= volume

Now we will put the values in formula.

d = 52.0 g/ 17.1 cm³

d = 3.0 g/cm³

It is given in question the density of aluminum is 2.7 g/cm³. The given metal sample is not aluminum because its density is 3.0 g/cm³.

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What is the energy of a photon with wavelength of 670.8?
Sliva [168]
<span>The velocity of a wave is calculated by v = λf. From this equation we can take the frequency f = v / λ and substitute in the energy equation to find a new equation for the calculation of the energy from the wavelength: E = hc / λ</span>


To calculate the photon energy, in eV (Electrovolt), when we have the value of the wavelength λ (necessarily given in Å - angstrom), we use an alternative equation given by:
E =  \frac{12400}{\lambda}

Data: 670.8 Å

Solving:
E = \frac{12400}{\lambda}
E = \frac{12400}{670.8}
\boxed{E \approx 18,4eV}
8 0
3 years ago
A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.9
rjkz [21]

Answer:

The mass % of BaCl2 is 47.24 %

Explanation:

Step 1: Data given

Molar mass BaSO4 = 233.38 g/mol

Molar mass BaCl2 = 208.23 g/mol

Step 2: The balanced equation

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)

Step 3: Calculate moles BaSO4

Moles BaSO4 = mass BaSO4 / molar mass BaSO4

Moles BaSO4 = 2.113 grams / 233.38 g/mol

Moles BaSO4 = 0.00905 moles

Step 4: Calculate moles BaCl2

For 1 mol BaCl2 we need 1 mol Na2SO4 to produce 1 mol BaSO4 and 2 moles NaCl

For 0.00905 moles BaSO4 we need 0.00905 moles BaCl2

Step 5: Calculate mass BaCl2

Mass BaCl2 = moles BaCl2 * molar mass BaCl2

Mass BaCl2 = 0.00905 moles *208.23 g/mol

Mass BaCl2 = 1.884 grams

Step 6: Calculate % BaCl2

% BaCl2 = (1.884 / 3.988 ) * 100%

% BaCl2 = 47.24 %

The mass % of BaCl2 is 47.24 %

7 0
3 years ago
Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of
Neko [114]

Answer:

10.60 grams of silane gas are formed.

Explanation:

From the reaction:

Mg₂Si(s) + 4H₂O(l) → 2Mg(OH)₂(aq) + SiH₄(g)          

We know that the limiting reactant is Mg₂Si, so to find the mass of SiH₄ formed we need to calculate the number of moles of Mg₂Si:

\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}}

Where:

m: is the mass of Mg₂Si = 25.0 g

M: is the molar mass of Mg₂Si = 76.69 g/mol

\eta_{Mg_{2}Si} = \frac{m_{Mg_{2}Si}}{M_{Mg_{2}Si}} = \frac{25.0 g}{76.69 g/mol} = 0.33 moles

Now, the stoichiometric relation between Mg₂Si and SiH₄ is 1:1 so:

\eta_{Mg_{2}Si} = \eta_{SiH_{4}} = 0.33 moles

Finally, the mass of SiH₄ is:

m_{SiH_{4}} = \eta_{SiH_{4}}*M_{SiH_{4}} = 0.33 moles*32.12 g/mol = 10.60 g

Therefore, 10.60 grams of silane gas are formed.

I hope it helps you!    

3 0
3 years ago
What is cellular respiration?
tankabanditka [31]
Heya

ques is what is cellular respiration?

the ans is Exchanging O2 for CO2 in the blood within the lungs.

thank u
8 0
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Answer: De câte cărămizi am nevoie? Pentru un perete de cărămidă cu strat singular, înmulțiți lungimea peretelui cu înălțimea pentru a obține zona. Înmulțiți acea zonă cu 60 pentru a obține numărul de cărămizi de care ar trebui să aveți nevoie, apoi adăugați 10% pentru risipă. Acesta este răspunsul scurt și presupune dimensiuni „standard” de cărămidă și mortar.

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3 years ago
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