Answer: x^2+6x+8
Step-by-step explanation: Using FOIL, you multiply the First, Outer, Inner, and Last parts of the problem. :)
x^2+4x+2x+8
x^2+6x+8
What is the black box? and u solve that by forgetting the c is there so 4-10= -6 or -6c
![f(x) = -6x^2 + 7x + 4](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-6x%5E2%20%2B%207x%20%2B%204)
Step-by-step explanation:
For x = 1
(1)
For x = -3,
![a(-3)^2 + b(-3) + c = -71](https://tex.z-dn.net/?f=a%28-3%29%5E2%20%2B%20b%28-3%29%20%2B%20c%20%3D%20-71)
(2)
For x = 3,
![a(3)^2 + b(3) + c = -29](https://tex.z-dn.net/?f=a%283%29%5E2%20%2B%20b%283%29%20%2B%20c%20%3D%20-29)
(3)
Let's add Eqn(2) and Eqn(3) together to eliminate b:
(4)
Next, multiply Eqn(1) by 3 and then add to Eqn(2) to get
(5)
Then we want to eliminate c by multiplying Eqn(4) by -2 and then adding to Eqn(5) and we will get
![-24a = 144 \Rightarrow a = -6](https://tex.z-dn.net/?f=-24a%20%3D%20144%20%5CRightarrow%20%20a%20%3D%20-6)
Now that we have the value for a, we can use either Eqn(4) or Eqn(5) to solve for c and we will get
![12(-6) + 4c = -56 \Rightarrow c = 4](https://tex.z-dn.net/?f=12%28-6%29%20%2B%204c%20%3D%20-56%20%5CRightarrow%20c%20%3D%204)
Using the values of a and c on Eqn(1), we find that
so therefore, our function f(x) has a form
![f(x) = -6x^2 + 7x + 4](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-6x%5E2%20%2B%207x%20%2B%204)
238 = 2*7*17
374 = 2*11*17
So GCD(238, 374) would be 2*17 = 34
Answer:
She is wrong
Step-by-step explanation:
in one gallon there is 128 ounces, and 2 would make it 256.
40 - 8 ounce cups would make it 320 ounces, therefore she would need 3 gallons at least.