Answer: here u go ig
Step-by-step explanation:
Answer:
5x -12 = 3x +8 (set the two = each other because they are the same length)
2x- 12= 8 (subtract 3x from both sides)
2x = 20 (add 12 to both sides)
x=10 (what x= for both expressions)
5(10) -12 (plug it into the first one to see what the length is and to see they're =
50 - 12 ( I already multiplied, now subtract)
38 (what the length of TR is)
3(10) +8 (plug it in again but into the other expression)
30+8 (multiply and add)
38 (the two have the same answer, so the x-value is correct.)
38+38= 76 (add the lengths of RS and TR and you get the length of TS)
Step-by-step explanation:
I hope this helps :)
7 were in each pack because orginally he had 28 he gave four away. 7*4=28
E) 2
Remember that the first derivative of a function is the slope of the function at any specified point. We've been told that f(0) = -5 and that f'(x) is always less than or equal to 3. So let's look at the available options and see what the average slope would have to be in order to get the specified value of f(2).
A) -10: (-10 - -5)/(2 - 0) = -5/2 = -2.5
B) -5: (-5 - -5)/(2 - 0) = 0/2 = 0
C) 0: (0 - -5)/(2 - 0) = 5/2 = 2.5
D) 1: (1 - -5)/(2 - 0) = 6/2 = 3
E) 2: (2 - -5)/(2 - 0) = 7/2 = 3.5
Now taking into consideration the mean value theorem, the value of the function f'(x) has to have the value equal to the average slope between the two points at at least one point between the two given values. For options A, B, C, and D it's possible for f'(x) to return values that make that slope possible. However, for option E, the mean value theorem indicates that f'(x) has to have the value of 3.5 for at least 1 point between x=0 and x=2. And since we've been told that f'(x) is less than or equal to 3 for all possible values of x, that is in conflict and f(2) can not have the value of 2.
A = lw
525 = (25)(w)
525 = 25l
25 25
21 = w
