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yKpoI14uk [10]
3 years ago
11

SOMEBODY HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Grace [21]3 years ago
5 0

Answer:pls is it all we are to ans

Step-by-step explanation:

Degger [83]3 years ago
4 0

Answer:

82 degrees

Step-by-step explanation:

1. Measure of angle BAD + ABC = 180 degrees (definition of a parallelogram). Because ABC = 71, and CAD = 27, you get BAC + 71 +27 = 180. --> BAC = 82 degrees

2. BE * 2 = BD. This means that 2(2x+2) = 5x-3. This means 4x + 4 = 5x-3, which makes x = 7. AC = 2AE, which means that 2(4x-6) = AC, which means AC is 2(28-6), which makes AC = 44.

3. Because MNPQ is isosceles, NMQ = PQM. This also means PQM +NPQ = 180. NMQ = 30 +32 = 62. This makes NPQ + 62 = 180. NPQ = 118

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Answer:

They are congruent, they are right angles

Step-by-step explanation:

Just in general, all vertical angles are congruent.

But in this situation, perpendicular lines will always create right angles.

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2 years ago
Which expression is equivalent to the area of metal sheet required to make this square-shaped traffic sign? I WILL GIVE BRAINLYI
Dmitry_Shevchenko [17]

Answer:

4x^2+4x-1

Step-by-step explanation:

6 0
3 years ago
John has to build a box for his scouting project with a volume of 36 cubic centimeters.
prohojiy [21]

Answer:

John should build the box 3 cm high.

Step-by-step explanation:

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3 years ago
Find the mean of the following: 158, 213, 107, 213, and 213. If needed, round your answer to the nearest tenth
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4 0
3 years ago
Read 2 more answers
One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

5 0
3 years ago
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