Please helpp!! (algebra 1 problem look at picture for the problem)
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The ratio of the frequency of a prime rolled using the first two (ordinary)dice to the frequency of a prime rolled using the unusual die and one ordinary die is
There are a total of 36 equally probable ways the dice can fall
In the first case, primes are achieved for the following results:
- 2 (one way possible),
- 3 (two ways possible),
- 5 (4 ways possible),
- 7 (six ways possible), and
- 11 (2 ways possible.
So primes are achieved in a total of 15 ways.
In the second case, the prime possibilities are
- 3 (one way possible),
- 5 (two ways),
- 7 (3 ways),
- 11 (3 ways),
- 13 (3 ways), and
- 17 (just one way).
The total is 13 ways.
<h3>How to calculate the ratio of the frequency</h3>Therefore
How to calculate the ratio of the frequency is Mathematically given as
Frequency ratio is
For more information on dice,
visithttps://brainly.com/question/2264527
Answer:
y ≥ -x - 4
Step-by-step explanation:
Slope-point form of linear equation:
For ≤ or ≥ graph a solid line
For < or > graph a dashed line
For shading above the line: y ≥ or y >
For shading below the line: y ≤ or y <
Therefore, as the line is solid and shading is above the line: