calculate the mass of HNO3 obtained when 20.0g of KNO3 reacts completely with excess concentrated H2SO4

Chemistry

1 answer:

iragen [17]1 year ago

8 0

The mass of HNO3 obtained is 12.46 g from the given reaction.

The chemical reaction is :

Potassium Nitrate + Sulphuric acid ------> Potassium Bisulphate + Nitric acid.

The above reaction is basically used for the making of nitric acid.

Less than 200 degree celcius the Nitric acid if more than 200 degree celcius then it will form Potassium Sulphate.

Now,

1 mol of KNO3 reacts with1 mol of concentrated H2SO4 to give 1 mol HNO3

Molar Mass of KNO3 = 101.1 g

Molar mass of H2SO4 = 98.07 g

Mass of H2SO4 that can react with 20 g of KNO3 = (20 g* 98.07 g )/ 101.1 g

= 19.4 g

Molar mass of nitric acid= 63.01 g

Hence mass of nitric acid produced by 20 g of KNO3 = (20 g * 63.01 g ) / 101.1 g = 12.46 g

To know more about Nitric acid here :

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zhenek [66]

To find pH, use the following formula ---> pH= - log [H+]

so first we need to calculate the [H+] concentration using the OH concentration. to do this, we need to use this formula--> 1.0x10-14= [H+] X [OH-], so we solve for H+ and plug in

[H+]= 1.0X10-14/[OH-]---> 1.0 x 10-14/ 1.0 x 10-4= 1.0 x 10-10

now that we have the H+ concentration, we can solve of pH

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3 years ago

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Deffense [45]

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Explanation:

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In the case of the reaction:

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the equilibrium constant Kp is determined by the following expression:

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