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balandron [24]
3 years ago
13

If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7

Chemistry
1 answer:
LenaWriter [7]3 years ago
4 0
<span>0.48 grams. Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced. To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So 0.0075 mol * 63.546 g/mol = 0.476595 g. Round the results to 2 significant figures, giving 0.48 grams.</span>
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Which of the following methods for increasing the rate of chemical reaction increases the effectiveness of the interactions betw
denpristay [2]

Answer:

Increasing the surface area of the reactants

Explanation:

An increase in surface area of the reactant will always cause an increase in the rate of reaction. This is so because, an increase in the surface area of the reactant will cause the reactant particles to collide effectively thereby bringing about an increase in the reaction rate.

Collision theory suggests that for a reaction to occur, the reactant particles must collide with the right orientation. As the surface area of the reactants are increased, the reactants particles collide more with the right orientation bringing about definite increase in the rate of reaction.

3 0
3 years ago
In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
LiRa [457]

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

To calculate pH of gastric juice:

molarity of H^+ = 0.072

pH=-log[H^+]

pH=-log(0.072)=1.14

Thus the pH of the gastric juice is 1.14

3 0
3 years ago
_Al2O3+heat=_Al+_O2​
Natalka [10]

Answer:

6.

2AI2O3 + heat ->  4AI + 3O2

Reaction type: Combustion

7.

2AI+ 6HCl -> 3H2 + 2AlCl3

Reaction type: Single Replacement

8.

IDK

Reaction type: Double Replacement?

Explanation:

8 0
3 years ago
Mass of 0.432 moles of C8H9O4?
Fiesta28 [93]
Find one mole
8 C = 8 * 12 = 96
9 H = 1 * 9 = 9
4 O = 4 *16 = 64
Total = 169 

1 mol = 169 grams.
0.432 mol = x

1/0.432 = 169/x
x = 0.432 * 169
x = 73.0 grams
7 0
3 years ago
Read 2 more answers
The solute will dissolve quicker if the solute is more?
Vitek1552 [10]

Answer:

I think D. settled :)

Explanation:

5 0
3 years ago
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