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3 years ago

If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7

1 answer:

4 0

0.48 grams. Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced. To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So 0.0075 mol * 63.546 g/mol = 0.476595 g. Round the results to 2 significant figures, giving 0.48 grams.

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What is the correct sequence of coefficients when this equation is balanced? ___cs2(l) + ___o2(g) → ___co2(g) + ___so2(g)?

iris [78.8K]

Answer: the sequence is 1, 3, 1, 2.

Explanation:

1) Given equation: CS₂(l) + O₂(g) → CO₂(g) + SO₂(g)

2) To balance:

i) initially C is balanced: 1 atom in the left side, and 1 atom in the right sides

ii) Add coefficient 2 in front of SO₂ to have 2 atoms in each side.

That leads to: CS₂(l) + O₂(g) → CO₂(g) + 2SO₂(g)

iii) Count the O atoms; there are 2 atoms in the left, and 6 atoms in the right side. So, add a coefficient 3 in front of O₂ (in the left) and you get:

CS₂(l) + 3O₂(g) → CO₂(g) + 2SO₂(g)

4) You can verigy that now the equation is balanced:

C: 1 in the left, and 1 in the right

S: 2 in the left, and 2 in the right

O: 6 in the left, and 6 in the right.

5) So, the sequence is 1, 3, 1, 2.

Remember, when the none coefficient is shown it is because it is 1.

4 0

3 years ago

Read 2 more answers

When excess potassium hydroxide and H2SeO3 react whats the net ionic reaction for the acid-base rxn

Bad White [126]

The required net ionic equation is; 2H^+(aq) + 2OH^-(aq)-----> 2H2O(l)

The molecular reaction equation is;

H2SeO3(aq) + 2KOH(aq) -----> K2SeO3(aq) + 2H2O(l)

The complete ionic equation is;

2H^+(aq) + SeO3^2-(aq) + 2K^+(aq) + 2OH^-(aq)-----> 2K^+(aq) + SeO3^2-(aq) + 2H2O(l)

Net ionic equation;

2H^+(aq) + 2OH^-(aq)-----> 2H2O(l)

We can clearly see that this is a neutralization reaction hence water is the product of the net ionic equation.

Learn more:brainly.com/question/25150590

4 0

2 years ago

ammonia gas is used as refrigerant 0.474 atm. Pressure is required to change 2000 cm3 sample of ammonia initially at 1.0 atm to

Andreas93 [3]

Answer: The pressure required is 0.474 atm

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}V}$ (At constant temperature and number of moles)

The equation is,

${P_1V_1}={P_2V_2}$

where,

$P_1$ = initial pressure of gas = 1.0 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = $2000cm^3$

$V_2$ = final volume of gas = $4.22dm^3=4220cm^3$ ( $1dm^3=1000cm^3)$

Now put all the given values in the above equation, we get:

${1.0\times 2000}={P_2\times 4200}$

$P_2=0.474atm$

The pressure required is 0.474 atm

5 0

3 years ago

Coefficient - Subscript for K- 3) 4K CO Subscript for C Subscript for 0 -

Ulleksa [173]

Explanation:

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6 0

3 years ago

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In a reaction where an OH group is substituted with a Cl, 15.02 g of 3-phenyl-2-butanol (MW=150.2 g/mol) is the starting materia

Brrunno [24]

Answer:

16.81 g of C₁₀H₁₃Cl

Explanation:

When 3-phenyl-2-butanol reacts with HCl it undergoes a substitution reaction to form 2-chloro-3-phenylbutane and water.

C₁₀H₁₄O + HCl ⇄ C₁₀H₁₃Cl + H₂O

The molar mass of 3-phenyl-2-butanol is 150.2 g/mol and the molar mass of 2-chloro-3-phenylbutane is 168.1 g/mol. The molar ratio is 1:1. Then, for 15.02 g of 3-phenyl-2-butanol, the theoretical yield is:

$15.02gC_{10}H_{14}O.\frac{168.1gC_{10}H_{13}Cl}{150.2gC_{10}H_{14}O} =16.81gC_{10}H_{13}Cl$

8 0

4 years ago