The domain:The number of which the logarithm is taken must be greater than 0.

The base of the logarithm must be greater than 0 and not equal to 1.
* greater than 0:

*not equal to 1:

Sum up all the domain restrictions:
The solution:

Now if the base of the logarithm is less than 1, then you need to flip the sign when solving the inequality. If it's greater than 1, the sign remains the same.
* if the base is less than 1:

The inequality:

* if the base is greater than 1:


The inequality:
![\log_{8x^2-23x+15} (2x-2) \leq \log_{8x^2-23x+15} 1 \ \ \ \ \ \ \ |\hbox{the sign remains the same} \\ 2x-2 \leq 1 \\ 2x \leq 3 \\ x \leq \frac{3}{2} \\ x \leq 1 \frac{1}{2} \\ x \in (-\infty, 1 \frac{1}{2}] \\ \\ \hbox{including the condition that the base is greater than 1:} \\ x \in (-\infty, 1 \frac{1}{2}] \ \land \ x \in (2, \infty) \\ \Downarrow \\ x \in \emptyset](https://tex.z-dn.net/?f=%5Clog_%7B8x%5E2-23x%2B15%7D%20%282x-2%29%20%5Cleq%20%5Clog_%7B8x%5E2-23x%2B15%7D%201%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%7C%5Chbox%7Bthe%20sign%20remains%20the%20same%7D%20%5C%5C%202x-2%20%5Cleq%201%20%5C%5C%202x%20%5Cleq%203%20%5C%5C%20x%20%5Cleq%20%5Cfrac%7B3%7D%7B2%7D%20%5C%5C%20x%20%5Cleq%201%20%5Cfrac%7B1%7D%7B2%7D%20%5C%5C%20x%20%5Cin%20%28-%5Cinfty%2C%201%20%5Cfrac%7B1%7D%7B2%7D%5D%20%5C%5C%20%5C%5C%20%5Chbox%7Bincluding%20the%20condition%20that%20the%20base%20is%20greater%20than%201%3A%7D%20%5C%5C%20x%20%5Cin%20%28-%5Cinfty%2C%201%20%5Cfrac%7B1%7D%7B2%7D%5D%20%5C%20%5Cland%20%5C%20x%20%5Cin%20%282%2C%20%5Cinfty%29%20%5C%5C%20%5CDownarrow%20%5C%5C%20x%20%5Cin%20%5Cemptyset)
Sum up both solutions:
The final answer is:
$0.46 per ounce I think. Not 100%, a guess.
Answer:
PEMDAS DAT
Step-by-step explanation:
Hey there,
If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*h)(x)?
Based on my understanding, I believe that your correct answer would
be 2x2 – 16x + 30 because 2x^2-16x+30. Just by plugging in both 2x^2
and also 16x+30, so this would mean that 2x²-16x+30 would be your correct answer.
Hope this helps.
The measure of angle z is 27