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9 months ago

Neeeeeeeeed help please please

Mathematics

1 answer:

Liono4ka [1.6K]9 months ago

4 0

Answer:

Step-by-step explanation:

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Which rate convert to a unit rate of 12.50 per hour

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Answer: What rate do you mean? Thanks!

'please excuse me for this'

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3 years ago

Special right triangles, solve for x, y and z

Alika [10]

Answer:

x=14

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z=43

Step-by-step explanation:

hope it helps!

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2 years ago

An alloy is composed of nickel, zinc, and copper in a 7:2:9 ratio. How many kilograms of each metal is needed to make 3.8 kg of

Tamiku [17]

Ni : Zn: Cu = 7:2:9 =7x : 2x : 9x

7x+2x+9x = 3.8
18x=3.8
x=3.8/18=1.9/9≈0.21

Ni: 7x=7*0.21=1.47 ≈1.5 kg
Zn: 2x=2*0.21=0.42≈0.4 kg
Cu: 9x=9*0.21=1.89 ≈1.9 kg

Check 1.5+0.4+1.9 =3.8 True

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3 years ago

Consider this equation:

icang [17]

Answer:

d = (2z + 3)/(p) - z

5 0

3 years ago

In a survey conducted by the Gallup Organization, 1100 adult Americans were asked how many hours they worked in the previous we

const2013 [10]

Answer:

1) Increase the sample size

2) Decrease the confidence level

Step-by-step explanation:

The 95% confidence interval built for a sample size of 1100 adult Americans on how much they worked in previous week is:

42.7 to 44.5

We have to provide 2 recommendations on how to decrease the margin of Error. Margin of error is calculated as:

$M.E=z_{\frac{\alpha}{2} } \times \frac{\sigma}{\sqrt{n}}$

Here,

$z_{\frac{\alpha}{2} }$ is the critical z-value which depends on the confidence level. Higher the confidence level, higher will be the value of critical z and vice versa.

$\sigma$ is the population standard deviation, which will be a constant term and n is the sample size. Since n is in the denominator, increasing the value of n will decrease the value of Margin of Error.

Therefore, the 2 recommendations to decrease the Margin of error for the given case are:

Increase the sample size and make it more than 1100
Decrease the confidence level and make it lesser than 95%.

7 0

3 years ago