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jenyasd209 [6]
1 year ago
15

Neeeeeeeeed help please please

Mathematics
1 answer:
Liono4ka [1.6K]1 year ago
4 0

Answer:

Step-by-step explanation:

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It’s the second one :)
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write an equation that describes the proportional relationship between the number of days in the number of weeks in a given leng
KatRina [158]

Answer:

Week 1 Day 7

Week 2 Day 14

Week 4 Day 28

Week 8 Day 56

Week 10 Day 70

Let x represent the number of weeks

Let y represent the number of days

Use the ratio of the constant of proportionally in the equation y =kx

y = 14/7x

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Step-by-step explanation:

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3 years ago
Solve for x. 3^x−1=9^x+2 <br> Enter your answer in the box.
slava [35]

Answer:

-5 =x

Step-by-step explanation:

3^(x-1) = 9^(x+2)

Replace 9 with 3^2

3^(x-1) = 3^2^(x+2)

We know that a power to a power means the powers are multiplied

a^b^c = a^(b*c)

3^(x-1) = 3^(2x+2)

When the bases are the same, the powers have to be the same

x-1 = 2x+4

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x-x-1 =2x-x+4

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Subtract 4 from each side

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4 0
4 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
4 years ago
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kirza4 [7]

Step-by-step explanation:

14. 8

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21. 18

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3 years ago
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