Answer:
A
Step-by-step explanation:
if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is
(x-x1)(x-x2)+(y-y1)(y-y2)=0
reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0
center is (2,-4)
r=√(2²+(-4)²-(-14))
=√(4+16+14)
=√(34)
eq. of circle is (x-2)²+(y+4)²=34
or
(x²-4x)+(y²+8y)=14
(x²-4x+4)+(y²+8y+16)=14+4+16
(x-2)²+(y+4)²=34
Answer:
the answerr is 4
Step-by-step explanation:
please mark me the brainiest
Ok so you do 900 ÷ 10 which = 90 and 90 x 10 = 900 so the answer is 90
Answer: 42°
<u>Step-by-step explanation:</u>
HJ is an angle bisector of ∠IHK so
∠IHJ ≅ ∠KHJ ⇒ m∠IHJ = m∠KHJ
3a + 6 = 5a - 18
6 = 2a - 18
24 = 2a
12 = a
∠IHJ = 3a + 6
= 3(12) + 6
= 36 + 6
= 42
22+5d=-8x7d=56d+ -8x-4=32
22+5d=-56d+32
22+32=54 and -56d+5d=-51d
The answer would be 51d+54
