Answer: 60 adults and 60 students
Step-by-step explanation:
True I believe my friend.
The volumes will be the same, because the heights are equal and the cross-sectional areas at every level parallel to the bases are also equal.
The sample space is 22 words and out of it, 14 words are known to have meanings for the student. In the problem, we use 10 C8 + 10 C9 + 10 C10 to associate at least 8 words. The complete formula is (10 C8 * (14/22)^8 * (8/22)^2 + 10 C9 (14/22)^9 * (8/22)^1 + 10 C 10 (14/22)^10 * (8/22)^)0) that is equal to 0.233
