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Gelneren [198K]
3 years ago
6

Jordan and Jake each work during the summer. Jordan earns $9 per hour at her job. Jordan also gets a $10 weekly allowance. Jorda

n displayed her earnings in a table.
Hours: 0 1 2 3 4 5 6 7 8

Earnings: 10 19 28 37 46 55 64 73 82

Jake earns $6.50 per hour at his job. Jake also gets a $15 weekly allowance. Jake displayed his earnings in a graph. How many hours will it take for Jordan and Jake to earn the same amount of money?
I am desperate!!!
Mathematics
1 answer:
Arlecino [84]3 years ago
8 0
0 hours-
Jordan: 10
Jake: 15

1-
19
21.50

2-
28
28

They will have made the same amount of money after they have completed 2 hours of work each.

--------------------------

Another easy way to find the answer is to put the two into expressions and combine into an equation:

Jordan: 9x+10
Jake: 6.5x+15

Put into one equation:
9x+10=6.5x+15

Solve:

9x+10=6.5x+15

Step 1) Subtract 6.5x from both sides:

2.5x+10=15

Step 2) Subtract 10 from both sides:

2.5x=5

Step 3) Divide by 2.5 on both sides:

x=2

Step 4) Your answer:

You get the same 2 (hours)

If you need the value (Like how much money they made) then just plug in your x value to both expressions.

9x+10=
18+10=
28

6.5x+15=
13+15=
28
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A. Amount(hours worked)  

Step-by-step explanation:

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Let's convert the word expression to function notation:

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I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

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Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

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The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

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<u>Finally for the question c we have</u>

Degree: 5

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Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

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Answer:

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Part B:

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