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rodikova [14]
2 years ago
9

A 2. 26 l balloon of helium is at 30°c and 1. 61 atm, what is the pressure if the volume is increased to 4. 12 l?.

Chemistry
1 answer:
kipiarov [429]2 years ago
3 0

Therefore the pressure if the volume is increased to 4.12L the pressure is

P₂=0.636atm

<h3>What is helium?</h3>

Helium is a chemical element with the atomic number 2 and the letter He. It is a colourless, odourless, tasteless, non-toxic, inert, monatomic gas and the first member of the noble gas group in the periodic chartIt has the lowest melting and boiling points of all the elements.

<h3>What is the purpose of helium and is it a gas?</h3>

Since helium is a safe, non-flammable gas, it is frequently used to inflate balloons for festivities and parades. On the other hand, helium is a crucial component in several sectors, including high-tech manufacturing, medical technology, space exploration, and national security.

The second most prevalent element in the universe, helium, is scarce on Earth. It is the lightest noble gas, colourless, odourless, inert, and has a low boiling point. It is a byproduct of nuclear fusion and radioactive decay.

<h3>Briefing:</h3>

According to Boyle's Law:

P₁ V₁=P₂ V₂

P₁=1.61atm

V₁=2.26L

V₂=4.12L

P₂=(P₁ V₁)/V₂

P₂=((1.61atm)(2.26L))/4.12L

P₂=0.636atm

Boyle's Law states that the volume of a given quantity of gas at a constant temperature is inversely proportional to its pressure, so this makes sense. The pressure must decrease proportionally as the volume rises.

To know more about Helium visit:

brainly.com/question/1780577

#SPJ4

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ratelena [41]

Answer:

-191.7°C

Explanation:

P . V = n . R . T

That's the Ideal Gases Law. It can be useful to solve the question.

We replace data:

2.5 atm . 8 L = 3 mol . 0.082 L.atm/mol.K . T°

(2.5 atm . 8 L) / (3 mol . 0.082 L.atm/mol.K) = T°

T° = 81.3 K

We convert T° from K to C°

81.3K - 273 = -191.7°C

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