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rodikova [14]
1 year ago
9

A 2. 26 l balloon of helium is at 30°c and 1. 61 atm, what is the pressure if the volume is increased to 4. 12 l?.

Chemistry
1 answer:
kipiarov [429]1 year ago
3 0

Therefore the pressure if the volume is increased to 4.12L the pressure is

P₂=0.636atm

<h3>What is helium?</h3>

Helium is a chemical element with the atomic number 2 and the letter He. It is a colourless, odourless, tasteless, non-toxic, inert, monatomic gas and the first member of the noble gas group in the periodic chartIt has the lowest melting and boiling points of all the elements.

<h3>What is the purpose of helium and is it a gas?</h3>

Since helium is a safe, non-flammable gas, it is frequently used to inflate balloons for festivities and parades. On the other hand, helium is a crucial component in several sectors, including high-tech manufacturing, medical technology, space exploration, and national security.

The second most prevalent element in the universe, helium, is scarce on Earth. It is the lightest noble gas, colourless, odourless, inert, and has a low boiling point. It is a byproduct of nuclear fusion and radioactive decay.

<h3>Briefing:</h3>

According to Boyle's Law:

P₁ V₁=P₂ V₂

P₁=1.61atm

V₁=2.26L

V₂=4.12L

P₂=(P₁ V₁)/V₂

P₂=((1.61atm)(2.26L))/4.12L

P₂=0.636atm

Boyle's Law states that the volume of a given quantity of gas at a constant temperature is inversely proportional to its pressure, so this makes sense. The pressure must decrease proportionally as the volume rises.

To know more about Helium visit:

brainly.com/question/1780577

#SPJ4

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Answer:

0.052 M

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Explanation:

There is some missing info. I think this is the complete question.

<em>A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>

Step 1: Calculate the moles of glucose (solute)

The molar mass of glucose is 180.16 g/mol.

4.6 g × 1 mol/180.16 g = 0.026 mol

Step 2: Calculate the molarity of the solution

0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.026 mol / 0.500 L = 0.052 M

Step 3: Calculate the mass corresponding to 500 mL of the solvent

The solvent has a density of 0.87 g/mL.

500 mL × 0.87 g/mL = 435 g = 0.44 kg

Step 4: Calculate the molality of the solution

We will use the definition of molality.

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m = 0.026 mol / 0.44 kg = 0.059 m

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3 years ago
Calculate the ph of a 0.005 m solution of potassium oxide k2o
Alecsey [184]
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According to reaction K2O has base properties, so it forms a hydroxide in water.
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pOH= -log c(OH⁻) = -log 0.01 = 2

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3 0
3 years ago
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