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rodikova [14]
1 year ago
9

A 2. 26 l balloon of helium is at 30°c and 1. 61 atm, what is the pressure if the volume is increased to 4. 12 l?.

Chemistry
1 answer:
kipiarov [429]1 year ago
3 0

Therefore the pressure if the volume is increased to 4.12L the pressure is

P₂=0.636atm

<h3>What is helium?</h3>

Helium is a chemical element with the atomic number 2 and the letter He. It is a colourless, odourless, tasteless, non-toxic, inert, monatomic gas and the first member of the noble gas group in the periodic chartIt has the lowest melting and boiling points of all the elements.

<h3>What is the purpose of helium and is it a gas?</h3>

Since helium is a safe, non-flammable gas, it is frequently used to inflate balloons for festivities and parades. On the other hand, helium is a crucial component in several sectors, including high-tech manufacturing, medical technology, space exploration, and national security.

The second most prevalent element in the universe, helium, is scarce on Earth. It is the lightest noble gas, colourless, odourless, inert, and has a low boiling point. It is a byproduct of nuclear fusion and radioactive decay.

<h3>Briefing:</h3>

According to Boyle's Law:

P₁ V₁=P₂ V₂

P₁=1.61atm

V₁=2.26L

V₂=4.12L

P₂=(P₁ V₁)/V₂

P₂=((1.61atm)(2.26L))/4.12L

P₂=0.636atm

Boyle's Law states that the volume of a given quantity of gas at a constant temperature is inversely proportional to its pressure, so this makes sense. The pressure must decrease proportionally as the volume rises.

To know more about Helium visit:

brainly.com/question/1780577

#SPJ4

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A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

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I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
What is insulin's structure?<br> a.quaternary<br> b.secondary<br> c.primary<br> d.tertiary
svetoff [14.1K]

Answer:

A

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Quaternary structure of proteins is composed of two or more polypeptide chains. Insulin has two; one alpha  and one beta chain. The two chains are joined together by disulfide bonds at two points (at cysteines). Other examples of quaternary proteins structures are DNA polymerase and hemoglobin.

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