Lithium and oxygen react explosively to form Lithium oxide. How many moles of oxygen are required to form 7.25 moles of Lithium?
1 answer:
Answer
Moles of O2 = 1.81 mol
Explanation
<em>Given:</em>
moles of Lithium = 7.25 mol
<em>Required</em>: moles of oxygen.
Solution
Step 1: Write the reaction and balance it.
The reaction of Li and O is as follows:
Step 2: Use the stoichiometry to calculate the moles of oxygen.
The molar ratio between Li and O2 is 4:1
Therefore the moles of O2 = 7.25 x (1/4) = 1.81 mol
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Explanation:
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