How much heat is added if 0.814g of water increase in temperature by 0.351 degree C
1 answer:
Answer:
1·199 J
Explanation:
Given
Mass of water = 0·814 g = 0·814 × kg
Increase in temperature = 0·351 °C
Let the amount of heat added be Q J
Formula for heat added is
<h3>Q = m × s × ΔT</h3>where Q is the amount of heat transferred
m is the mass
s is the heat capacity
ΔT is the change in temperature
Heat capacity of water = 4200 J/kg °C
Applying the formula for heat added
Q = 0·814 × × 4200 × 0·351 = 1·199 J
∴ Amount of heat added = 1·199 J
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Answer:
12.7551
Explanation:
The given chemical equation follows:
The equilibrium constant for the above equation is 0.28.
We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:
The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
<u>Hence, the value of equilibrium constant for reverse reaction is 12.7551.</u>