How much heat is added if 0.814g of water increase in temperature by 0.351 degree C
1 answer:
Answer:
1·199 J
Explanation:
Given
Mass of water = 0·814 g = 0·814 × kg
Increase in temperature = 0·351 °C
Let the amount of heat added be Q J
Formula for heat added is
<h3>Q = m × s × ΔT</h3>where Q is the amount of heat transferred
m is the mass
s is the heat capacity
ΔT is the change in temperature
Heat capacity of water = 4200 J/kg °C
Applying the formula for heat added
Q = 0·814 × × 4200 × 0·351 = 1·199 J
∴ Amount of heat added = 1·199 J
You might be interested in
Answer:
HI (hydrogen iodide).
Explanation:
Hello,
In this case, since iodine is in group VIIA, it has seven valence electrons at its outer shell, which means that it only needs one bond to attain the octet. Moreover, since hydrogen has just one electron at its outer shell, one hydrogen turns out enough to obey the octet when hydrogen and iodine bond as shown below:
Therefore, the required formula is:
Which is hydrogen iodide.
Best regards.
According to Arrhenius theory, acid is a substance that releases H⁺ ions when dissolved in water.
In order to apply this theory, the substance must be soluble in water.
H₂SO₄ is highly soluble in water. It undergoes following dissociation reaction when dissolved in water.
From the above equation, we can see that H₂SO₄ forms 2 H⁺ ions when dissolved in water. Therefore it behaves as an acid according to Arrhenius theory.