Answer:
Rate = 116m⁻¹s⁻¹[lactose][H]⁺
Explanation:
the formula for rate of reaction is given as
Rate = k[lactose]∧α[H]⁺∧β
we solve for the value of α and β
([lactose]₁/[lactose]₂)∧α
α = 
when we divide this equation
α = 
α = 1
we find β
R₁/R₂ = 0.01/0.02(0.001/0.001)∧β
0.00116/0.00232 = 0.5(1)∧β
β = 1
Rate = k[lactose]∧α[H]⁺∧β
we have to find the value for k
k = 0.00116/0.01(0.001)
k = 0.00116/0.00001
= 116m⁻¹s⁻¹
<u>Rate = 116m⁻¹s⁻¹[lactose][H]⁺</u>
<span>oxygen is a mixture and a rock is a pure substance.</span>
1.5*9.8*1.2
since the formula is force * distance.
1.2 is the distance. the force is gravity on the object (1.5*9.8)
The answer is 17.64 J . (18 J with sig figs)
V is used to indicate Ecell ( just look at what measurement is simplified to V) <span />