The red semicircle shown in the weather chart represents warm front.
The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.
Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be
g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.
Answer:
54g
Explanation:
Given parameters:
Number of moles of H₂O = 3 moles
Unknown:
mass of water = ?
Solution:
To solve this problem, we use the expression below:
mass = number of moles x molar mass
Molar mass of H₂O = 2(1) + 16 = 18g/mol
Mass of water = 3 x 18 = 54g
Answer:
<h3>The answer is 10 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 300 g
volume = final volume of water - initial volume of water
volume = 40 - 10 = 30 mL
We have

We have the final answer as
<h3>10 g/mL</h3>
Hope this helps you
Answer:
Steam always has more thermal energy than ice.
Explanation: