if only 0.264 g of ca(oh)2 dissolves in enough water to give 0.178 l of aqueous solution at a given temperature, what is the ksp

Question

1 year ago

11

value for calcium hydroxide at this temperature?

1 answer:

Maurinko [17] · Answer 1 · 2024-03-01T16:13:17+03:00

The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.

Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.

Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water

The solution equilibrium is

Ca(OH)² = Ca + 2OH

The molar solubility is

0.186 / 74.00 / 0.230 = 0.0109 M

The ksp value will be

Ksp = (s) (2S)²

Putting the values in the formula

(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.

Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.

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