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Anna [14]
3 years ago
6

The solubility of potassium sulfate in water is 16 grams per 100

Chemistry
1 answer:
kicyunya [14]3 years ago
7 0

The answer is 25 grams for this question

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Ght
Murljashka [212]

Answer 78

Explanation:

omg long

4 0
3 years ago
NH3 is nitrogen trihydride (ammonia) and BF3 is boron trifluoride. What is the name for AlCl3 and why
mezya [45]

Aluminum chloride - It does not have the prefix "tri-" since it is ionic. The other compounds listed in the question are covalent and require prefixes.

5 0
3 years ago
Which of the following would not be a clear indication of a chemical change
Alekssandra [29.7K]

I believe the answer is "After adding two substances together a new order is detected" because nearly all of the other answers suggest a chemical change has taken place. The reason I say "almost" is because answer two and four results in bubbles forming so the answer cannot be both. The only one to not clearly show a chemical change has occurred is the last answer.

3 0
3 years ago
The element which has atomic number 17 is considered from... A. Metals B. Non-metals C. Noble gas D. No correct answer Please ex
jeyben [28]

Answer:

B. Non-metals

Explanation:

The element with the atomic number of 17 is Cl.

Chlorine belongs to the group 7 in the periodic table. It is a non metal.

Correct option: B. Non-metals

7 0
3 years ago
Consider a buffer solution that is 0.50 M in NH3 and 0.20 M in NH4Cl. For ammonia, pKb=4.75. Calculate the pH of 1.0 L of the so
vladimir2022 [97]
You have 0.50 mol of NH3 and 0.20 mol of NH4+ to start (NH4Cl dissolves completely), given the molarity and 1.0 L solution.

30.0 mL of 1.0 M HCl is 0.0300 mol of HCl. This will react with the NH3 to produced 0.030 mol of NH4+.

You now have 0.47 mol NH3 and 0.23 mol NH4+. Now use the Henderson-Hasselbach equation to calculate your pH. The equation says to use concentration of acid and base, but you can just use the moles of them because it doesn’t make a difference.

pH = pKa + log(base/acid)

pKa = 14 - pKb = 14 - 4.75 = 9.25

pH = 9.25 + log(0.47/0.23) = 9.56
5 0
3 years ago
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