Are the bonds in each of the following substances ionic, nonpolar covalent, or polar covalent? Arrange the substances with polar
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It takes 0.26 minutes to travel 1000 feet
<u>Solution:</u>
Given that car traveling at a constant speed travels 175 miles in four hours
Distance = 175 miles
Time taken = 4 hours
Convert the units to feet and minute
Given that,
1 mile = 5280 feet
175 miles = 5280 x 175 feet = 918720 feet
Also we know that,
1 hour = 60 minutes
4 hours = 60 x 4 minutes = 240 minutes
Thus, we got,
Distance = 918720 feet
Time taken = 240 minutes
<em><u>Find the speed of car</u></em>
<em><u>Speed is given by formula:</u></em>
Thus speed of car is 3828 feet per minute
<em><u>How many minutes will it take for the car to travel 1000 feet?</u></em>
Let "x" be the minutes needed for 1000 feet
speed of car is 3828 feet per minute
1 minute = 3828 feet
x minute = 1000 feet
This forms a proportion. We can solve by cross multiplying
Thus it takes 0.26 minutes to travel 1000 feet
This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.
Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:
Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:
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Answer:
The theoretical yield of alum is 19.873 grams and percent yield for this alum synthesis is 45.33%.
Explanation:
Mass of bottle = 10.221 g
Mass of bottle with aluminium pieces = 11.353 g
Mass of aluminium = 11.353 g - 10.221 g = 1.132 g
Mass of alum and bottle = 19.230 g
Mass of alum = 19.230 g - 10.221 g = 9.009 g
Experimental yield of alum = 9.009 g
Theoretical yield of alum:
Moles of aluminium =
According to reaction, 2 moles of aluminum gives 2 moles of alum.
Then 0.041926 mol aluminium will give :
of alum.
Mass of 0.041926 moles of alum:
0.041926 mol × 474 g/mol= 19.873 g
Theoretical yield of alum = 19.873 g
Percentage yield:
Percentage yield of the alum:
The theoretical yield of alum is 19.873 grams and percent yield for this alum synthesis is 45.33%.