3 is incorrect, should be 28.9
16^2 + 18^2 = EG^2
256 + 324
580 = EG^2
EG ≈ 24.08
16^2 + 24.08^2 = AG^2
256 + 580 = AG^2
836 = AG^2
AG ≈ 28.9
5 is incorrect:
The base is 8.
Draw an altitude the base.
Since the triangle is isoceles, it divides the base in half.
Half of that base is 4.
Two right triangles have been formed with one leg 4 and hypotenuse 8.
4^2 + b^2 = 8^2
16 + b^2 = 64
b^2 = 48
b ≈ 6.93
The height of the triangle is 6.93, the base is 8.
A = bh/2 = 8*6.93/2 ≈ 27.7 ≈ 28
-6a-5=-95 Given
-6(15)-5=-95 Substitution
a=15 idk the reason im not real good at this but i tried!
Hope you have a nice day
These are all linear equations:<span>y = 2x + 1
5x = 6 + 3y
<span>y/2 = 3 − x</span></span>
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