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Pani-rosa [81]
1 year ago
7

What is the kinetic energy of a 328 kg object that is moving at s speed of 10 m/s

Chemistry
1 answer:
Advocard [28]1 year ago
6 0

16400 Joules is the kinetic energy of a 328kg object with a velocity of 10m/s.

<h3>What is the kinetic energy of the object?</h3>

Kinetic energy is simply energy possessed by a body in motion.

Kinetic energy is expressed as;

Kinetic energy = 1/2 × m × v²

Where v is velocity and m is mass of the object,

Given the data in the question;

  • Mass of the object m = 328kg
  • Velocity of the object = 10m/s
  • Kinetic energy = ?

To determine the kinetic energy of the object, plug the given values into the formula above.

Kinetic energy = 1/2 × m × v²

Kinetic energy = 1/2 × 328kg × (10m/s)²

Kinetic energy = 1/2 × 328kg × 100m²/s²

Kinetic energy = 328kg × 50m²/s²

Kinetic energy = 16400kgm²/s²

Kinetic energy = 16400J

Therefore, the kinetic energy 16400 Joules.

Learn more about kinetic energy here: brainly.com/question/27397088

#SPJ1

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Putting the values we get :

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Answer:

1.90 atm

Explanation:

Using ideal gas equation as:

PV=nRT

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P is the pressure

V is the volume

n is the number of moles

T is the temperature  

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According to above equation, at constant Volume and number of moles, pressure is directly proportional to the temperature. So,

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Given ,  

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T₁ = 23 °C

T₂ = 100 °C  ( boiling point of water )

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

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T₂ = (100 + 273.15) K = 373.15 K  

Using above equation as:

\frac{1.51}{296.15}=\frac{P_2}{373.15}

P_2=\frac{1.51\cdot \:373.15}{296.15}\ atm

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