A quantity of an ideal gas is compressed to half its initial volume. the process may be adiabatic, isothermal or isobaric. the g
1 answer:
the greatest amount of work is required if the process is adiabatic.The correct option is adiabatic.
The process in which heat is constant is called adiabatic process.
The The process in which temperature is constant is called isothermal process.
The process in which pressure is constant is called isobaric process.
The P-V diagram for adiabatic , isothermal and isobaric process is given below.
Work done in process = area encloses by P-V diagram axis . Since area under the curve is maximum for adiabatic process which is shown in the above diagram. So, work done by the gas will be maximum for adiabatic process.
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Answer: The volume occupied by 2.50 moles of gas at STP is 56.0L
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = ?
n = number of moles = 2.50
R = gas constant =
T =temperature = (at STP)
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