A quantity of an ideal gas is compressed to half its initial volume. the process may be adiabatic, isothermal or isobaric. the g
1 answer:
the greatest amount of work is required if the process is adiabatic.The correct option is adiabatic.
The process in which heat is constant is called adiabatic process.
The The process in which temperature is constant is called isothermal process.
The process in which pressure is constant is called isobaric process.
The P-V diagram for adiabatic , isothermal and isobaric process is given below.
Work done in process = area encloses by P-V diagram axis . Since area under the curve is maximum for adiabatic process which is shown in the above diagram. So, work done by the gas will be maximum for adiabatic process.
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Answer : The final equilibrium temperature of the water and iron is, 537.12 K
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of iron = 560 J/(kg.K)
= specific heat of water = 4186 J/(kg.K)
= mass of iron = 825 g
= mass of water = 40 g
= final temperature of water and iron = ?
= initial temperature of iron =
= initial temperature of water =
Now put all the given values in the above formula, we get:
Therefore, the final equilibrium temperature of the water and iron is, 537.12 K