How many cm3 are there in 0.25 dm3?

Part C<br> Number of molecules in 8.437x10-2 mol C6H6

N76 [4]

Answer:

There are $5.08\times 10^{22}\ \text{molecules of}\ C_6H_6$

Explanation:

In this problem, we need to find the number of molecules in $8.437\times 10^{-2}$ mol of $C_6H_6$ .

The molar mass of $C_6H_6$ is $6\times 12+1\times 6=78\ g/mol$

No of moles = mass/molar mass

We can find mass from above formula.

$m=n\times M\\\\m=8.437\times 10^{-2}\ mol\times 78\ g/mol\\\\m=6.58\ g$

Also,

No of moles = no of molecules/Avogadro number

$N=n\times N_A\\\\N=8.437\times 10^{-2}\times 6.023\times 10^{23}\\\\N=5.08\times 10^{22}\ \text{molecules}$

Hence, there are $5.08\times 10^{22}\ \text{molecules of}\ C_6H_6$

5 0

3 years ago

Suppose the decomposition of dinitrogen monoxide proceeds by the following mechanism:

photoshop1234 [79]

Answer:

Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)

Part B: -r = K*[N₂O]²

Part C: K= k1*k2

Explanation:

Part A

To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).

N₂O(g) ⇄ N₂(g) + O(g)

N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)

---------------------------------------------

2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)

2N₂O(g) ⇄ 2N₂(g) + O₂(g)

Part B

The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.

Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:

-r = K*[N₂O]²

Part C

Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:

K= k1*k2

8 0

4 years ago

Pls help Which statement is true about the environment of urban areas?

wel

The correct answer is A. Urban areas have higher temperatures.

Explanation

Urban Area is a term to refer to cities. Urban areas are characterized by having a developed infrastructure (wide roads, vehicular bridges, wide platforms, tall buildings, residential areas, industrial areas, among others).

Recent studies affirm that urban areas are warmer than surrounding areas; This phenomenon is because the materials with are built buildings, roads, houses, and others, concentrate the sun's rays, increasing the temperature of cities. In addition, the lack of trees deepens this phenomenon, because the trees contribute to cooling by physicochemical processes such as evapotranspiration.

According to the above, it is possible to affirm that urban areas are hotter than their surrounding area because they lack vegetation, and the materials with which it is built contribute to the increase in temperature.

On the other hand, urban areas are characterized by habitat fragmentation, more problems with soil erosion, and less rain infiltration into the soil.

Learn more in: brainly.com/question/23587978

6 0

3 years ago

In which aqueous solution will the most ZnS dissolve?

sineoko [7]

1) 0.1 M NaCl
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8 0

4 years ago

Read 2 more answers

When nitrogen gas (N2) reacts with hydrogen gas(H) ammonia gas (NH3) is formed. How many grams of hydrogen gas are required to r

kupik [55]

Mass of Hydrogen gas required to react : 0.936 g