Aluminium isn’t a compound as it is an element
Vapor pressure of a liquid increases with increasing temperature because increasing the temperature results in increasing kinetic energy and increase in molecular transition and motion.
What is Vapor Pressure?
- The pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases (solid or liquid) at a specific temperature in a closed system is referred to as vapor pressure.
- A liquid's evaporation rate can be determined by looking at the equilibrium vapor pressure. It has to do with how often particles tend to float away from liquids (or a solid).
- Volatile is a term used to describe a chemical that has a high vapor pressure at room temperature. Vapor pressure is the force that vapor exerts when it is present above a liquid surface.
- A liquid's molecules have an increasing kinetic energy as its temperature rises. The more molecules that convert into a vapor as a result of an increase in molecular kinetic energy, the higher the vapor pressure will be.
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Answer:
Compound X has the formula C8H14.
X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?
Explanation:
The degree of unsaturation in the given molecule C8H14 is:
DU=(Cn+1)-Hn/2-Xn/2+Nn/2
where,
Cn=number of carbon atoms
Hn=number of hydrogen atoms
Xn=number of halogen atoms
Nn=number of nitrogen atoms
C8H14:
DU=(8+1)-14/2
=>DU=9-7 =2
Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.
X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.
This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.
Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).
So, the molecule has a ring and double bond CH2.
Based on the given data the structure of compound X is shown below:
The reaction sequence is shown below:
Solve for x.
pv=xrt
Flip the equation.
rtx=pv
Divide both sides by rt.
rtx.rt = pv/rt
x = pv / rt
Answer:

Explanation:
There are two ways of looking at this problem. The first way, slightly more advanced, is to understand that the carbocation formed is an intermediate in this reaction: it is formed in one step and consumed in the subsequent step.
Secondly, we have hydroxide involved as our reactant, so it should be our second reactant in the second bimolecular step.
Thirdly, the product formed would be a combination of the anion and cation, one of our products, this means we have the following second step:

Another way is to verify this knowing that by adding all of the steps should yield a net equation, notice if we add the two steps together (reactants on one side and products on the other), we obtain:

Notice that the intermediate carbocation cancels out on both sides to yield the final net equation:

This means we have the correct second step.