Answer:
≈ 0.10M
Explanation:
[A]o = 0.27M
Rate constant, k = 0.75 s−1
[A] = ?
time, t = 1.3
Integrated formular for a first order reaction is given as;
ln[A] = ln[A]o − kt
ln[A] = ln(0.27) - 0.75(1.3)
ln[A] = -1.309 - 0.975
ln[A] = -2.284
[A] = 0.1019M ≈ 0.10M
Answer:
952.2g SO3
Explanation:
Molar mass of C4H8S2 is 120.2363 g/mol
Mol in 750.0g = 750.0/120.2363 = 6.238 mol
1mol C4H8S2 produces 2 mol SO3
6.238 mol will produce 2×6.238 = 12.476 mol SO3
Molar mass SO3 = 32+3×16 = 80.0g/mol
Theoretical yield = 12.476×80.0 = 998.08g
The actual yield is 95.4%
Actual mass-produced = 95.4/100×998.08 = 952.2g SO3 produced
Hope it will help you.
the answer is C, natural gas.. hope it helps
STP conditions imply a temperature of 273.15 K and a pressure of 100 kPa. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. Likewise, 0.5 moles will occupy half the volume 1 mole occupies.
